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Chemistry Exam 3 Cheat Sheet (DRAFT) by

Balancing Equations Stoichiometry Formula Determination Limiting Reagents

This is a draft cheat sheet. It is a work in progress and is not finished yet.

Termin­ology

Reactants
substances consumed during a chemical reaction
Products
substances formed as a result of a chemical reaction
Chemical Equation
a descri­ption of the identities and propor­tions of the reactants and the products in a chemical reaction
Balanced Chemical Equation
total number of atoms of each element are the same on the right and left side of the reaction arrow
Law of Conser­vation of Mass
the principle that the sum of the masses in a chemical reaction is equal to the sum of the masses of the products
Stoich­iometry
the study of the numerical relati­onship between chemical quantities in a chemical reaction
Phase Symbols
represent physical states of reactants and products: (g) gases, (l) liquids, (s) solids, (aq) aqueous solution

7.2 Writing Balanced Chemical Equations

Chemical Equations relate the quantities of substances consumed and produced in chemical reactions
Concepts of Mole & Molar Mass describe macros­copic quantities of substances in terms of the number of particles they contain
Combin­ation Reaction a reaction in which two or more substances form a single product
Combustion Reactions a rapid reaction between fuel and oxygen that produces and releases energy
Lack of any coeffi­cients indicates that one atom of something reacts with a single atom of something else to produce one molecule of product
C(s) + O2(g) -> CO2(g)
+ ->
Any number of moles (X moles) can react with an equal number of moles of another reactant (Y moles) to produce the same quantity of product (XY moles)

7.2 Desc­ribing Chemical Reacti­ons

S(s) + O2(g) -> SO2(g)
+ ->
4 Ways to Describe Chemical Reactions
1) One atom of sulfur reacts with one molecule of oxygen to produce one molecule of sulfur dioxide
2) The coeffi­cients tell us that one mole of sulfur reacts with one mole of oxygen to produce one mole of sulfur dioxide
3) Avogadro's constant describes that 6.022 x 1023 atoms of sulfur react with 6.022 x 1023 molecules of oxygen forming 6.022 x 1023 molecules of sulfur dioxide
4) The Molar Masses of the reactants and products allow us to say that 32.06 grams of sulfur react with 32.00 grams of oxygen to produce 64.06 grams of sulfur dioxide

General Rules for Balancing Equati­ons

First attempts at balancing equations may not work. Try a different approach starting with a different element.
Balance pure elements last (O2, H2, N2)
Do not break up polyatomic ions (SO42-)

4-Step Method for Writing Balanced Equati­ons

Element
Sulfur
1) Write a prelim­inary expression containing a single particle (atom, molecule, or formula unit) of each reactant and product with a reaction arrow separating reactants from products. Include phase symbols indicating physical states.
SO2(g) + O2(g) -> SO3(g)
2) Check whether the expression is balanced by counting the atoms of each element on each side of the reaction arrow.
Reactant Side
1
Product Side
1
Balanced?
yes
Element
Oxygen
Reactant Side
2+2 = 4
Product Side
3
Balanced?
no
3) Choose an element that appears in only one reactant and one product and balance it first.
The only element that occurs only once on each side of the reaction arrow in this equation is sulfur, but it is already balanced, so this step can be skipped.
4) Choose coeffi­cients for the other substances os that the number of atoms for each element is the same on both sides of the reaction arrow.
 

Reaction Stoich­iometry

Ratio of Coeffi­cients in a Chemical Reaction (Mole Ratio)
* specify the relative amounts in molecules or moles of each of the substances involved in the reaction
* act as a conversion factor between the amount in moles/­mol­ecules of the reactants and products
* can be used to determine how much of one reactant is needed to completely react with another quantity of the other reactant

Example Ratio of Coeffi­cients

if 22.0 moles of C8H18 are burned, how many moles of CO2 form?
Stoich­iom­etric Ratio
22.0 mol C8H18 x 16 mol CO2/2 mol C8H18 = 176 mol CO2