\documentclass[10pt,a4paper]{article}

% Packages
\usepackage{fancyhdr}           % For header and footer
\usepackage{multicol}           % Allows multicols in tables
\usepackage{tabularx}           % Intelligent column widths
\usepackage{tabulary}           % Used in header and footer
\usepackage{hhline}             % Border under tables
\usepackage{graphicx}           % For images
\usepackage{xcolor}             % For hex colours
%\usepackage[utf8x]{inputenc}    % For unicode character support
\usepackage[T1]{fontenc}        % Without this we get weird character replacements
\usepackage{colortbl}           % For coloured tables
\usepackage{setspace}           % For line height
\usepackage{lastpage}           % Needed for total page number
\usepackage{seqsplit}           % Splits long words.
%\usepackage{opensans}          % Can't make this work so far. Shame. Would be lovely.
\usepackage[normalem]{ulem}     % For underlining links
% Most of the following are not required for the majority
% of cheat sheets but are needed for some symbol support.
\usepackage{amsmath}            % Symbols
\usepackage{MnSymbol}           % Symbols
\usepackage{wasysym}            % Symbols
%\usepackage[english,german,french,spanish,italian]{babel}              % Languages

% Document Info
\author{W00kin}
\pdfinfo{
  /Title (chemistry-exam-3.pdf)
  /Creator (Cheatography)
  /Author (W00kin)
  /Subject (Chemistry Exam 3 Cheat Sheet)
}

% Lengths and widths
\addtolength{\textwidth}{6cm}
\addtolength{\textheight}{-1cm}
\addtolength{\hoffset}{-3cm}
\addtolength{\voffset}{-2cm}
\setlength{\tabcolsep}{0.2cm} % Space between columns
\setlength{\headsep}{-12pt} % Reduce space between header and content
\setlength{\headheight}{85pt} % If less, LaTeX automatically increases it
\renewcommand{\footrulewidth}{0pt} % Remove footer line
\renewcommand{\headrulewidth}{0pt} % Remove header line
\renewcommand{\seqinsert}{\ifmmode\allowbreak\else\-\fi} % Hyphens in seqsplit
% This two commands together give roughly
% the right line height in the tables
\renewcommand{\arraystretch}{1.3}
\onehalfspacing

% Commands
\newcommand{\SetRowColor}[1]{\noalign{\gdef\RowColorName{#1}}\rowcolor{\RowColorName}} % Shortcut for row colour
\newcommand{\mymulticolumn}[3]{\multicolumn{#1}{>{\columncolor{\RowColorName}}#2}{#3}} % For coloured multi-cols
\newcolumntype{x}[1]{>{\raggedright}p{#1}} % New column types for ragged-right paragraph columns
\newcommand{\tn}{\tabularnewline} % Required as custom column type in use

% Font and Colours
\definecolor{HeadBackground}{HTML}{333333}
\definecolor{FootBackground}{HTML}{666666}
\definecolor{TextColor}{HTML}{333333}
\definecolor{DarkBackground}{HTML}{8DBAB7}
\definecolor{LightBackground}{HTML}{F0F6F6}
\renewcommand{\familydefault}{\sfdefault}
\color{TextColor}

% Header and Footer
\pagestyle{fancy}
\fancyhead{} % Set header to blank
\fancyfoot{} % Set footer to blank
\fancyhead[L]{
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
    \SetRowColor{DarkBackground}
    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
    }
\end{tabulary}
\columnbreak
\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Chemistry Exam 3 Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{W00kin} via \textcolor{DarkBackground}{\uline{cheatography.com/170869/cs/35811/}}}
\end{tabulary}
\end{multicols}}

\fancyfoot[L]{ \footnotesize
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{LL}
  \SetRowColor{FootBackground}
  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}W00kin \\
  \uline{cheatography.com/w00kin} \\
  \end{tabulary}
\vfill
\columnbreak
\begin{tabulary}{5.8cm}{L}
  \SetRowColor{FootBackground}
  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 1st December, 2022.\\
   Page {\thepage} of \pageref{LastPage}.
\end{tabulary}
\vfill
\columnbreak
\begin{tabulary}{5.8cm}{L}
  \SetRowColor{FootBackground}
  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Sponsor}}  \\
  \SetRowColor{white}
  \vspace{-5pt}
  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
\end{tabulary}
\end{multicols}}




\begin{document}
\raggedright
\raggedcolumns

% Set font size to small. Switch to any value
% from this page to resize cheat sheet text:
% www.emerson.emory.edu/services/latex/latex_169.html
\footnotesize % Small font.

\begin{multicols*}{2}

\begin{tabularx}{8.4cm}{x{3.52 cm} x{4.48 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{8.4cm}}{\bf\textcolor{white}{Terminology}}  \tn
% Row 0
\SetRowColor{LightBackground}
{\bf{Reactants}} & substances consumed during a chemical reaction \tn 
% Row Count 3 (+ 3)
% Row 1
\SetRowColor{white}
{\bf{Products}} & substances formed as a result of a chemical reaction \tn 
% Row Count 6 (+ 3)
% Row 2
\SetRowColor{LightBackground}
{\bf{Chemical Equation}} & a description of the identities and proportions of the reactants and the products in a chemical reaction \tn 
% Row Count 11 (+ 5)
% Row 3
\SetRowColor{white}
{\bf{Balanced Chemical Equation}} & total number of atoms of each element are the same on the right and left side of the reaction arrow \tn 
% Row Count 16 (+ 5)
% Row 4
\SetRowColor{LightBackground}
{\bf{Law of Conservation of Mass}} & the principle that the sum of the masses in a chemical reaction is equal to the sum of the masses of the products \tn 
% Row Count 22 (+ 6)
% Row 5
\SetRowColor{white}
{\bf{Stoichiometry}} & the study of the numerical relationship between chemical quantities in a chemical reaction \tn 
% Row Count 27 (+ 5)
% Row 6
\SetRowColor{LightBackground}
{\bf{Phase Symbols}} & represent physical states of reactants and products: (g) gases, (l) liquids, (s) solids, (aq) aqueous solution \tn 
% Row Count 32 (+ 5)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{8.4cm}}{\bf\textcolor{white}{7.2 Writing Balanced Chemical Equations}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Chemical Equations}} relate the quantities of substances consumed and produced in chemical reactions} \tn 
% Row Count 3 (+ 3)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Concepts of Mole \& Molar Mass}} describe macroscopic quantities of substances in terms of the number of particles they contain} \tn 
% Row Count 6 (+ 3)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Combination Reaction}} a reaction in which two or more substances form a single product} \tn 
% Row Count 8 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Combustion Reactions}} a rapid reaction between fuel and oxygen that produces and releases energy} \tn 
% Row Count 10 (+ 2)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Lack of any coefficients}} indicates that one atom of something reacts with a single atom of something else to produce one molecule of product} \tn 
% Row Count 13 (+ 3)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{C(s) + O2(g) -\textgreater{} CO2(g)} \tn 
% Row Count 14 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{\{\{fa-circle\}\} + \{\{fa-circle-o\}\}\{\{fa-circle-o\}\} -\textgreater{}\{\{fa-circle-o\}\}\{\{fa-circle\}\}\{\{fa-circle-o\}\}} \tn 
% Row Count 16 (+ 2)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{Any number of moles (X moles) can react with an equal number of moles of another reactant (Y moles) to produce the same quantity of product (XY moles)} \tn 
% Row Count 19 (+ 3)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{8.4cm}}{\bf\textcolor{white}{7.2 {\bf{Describing Chemical Reactions}}}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{S(s) + O2(g) -\textgreater{} SO2(g)}}} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{\{\{fa-circle-o\}\} +\{\{fa-circle\}\}\{\{fa-circle\}\}  -\textgreater{}\{\{fa-circle\}\} \{\{fa-circle-o\}\}\{\{fa-circle\}\}} \tn 
% Row Count 3 (+ 2)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{4 Ways to Describe Chemical Reactions}}} \tn 
% Row Count 4 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{1) One {\bf{atom}} of sulfur reacts with one {\bf{molecule}} of oxygen to produce one {\bf{molecule}} of sulfur dioxide} \tn 
% Row Count 7 (+ 3)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{2) The {\bf{coefficients}} tell us that one {\bf{mole}} of sulfur reacts with one {\bf{mole}} of oxygen to produce one {\bf{mole}} of sulfur dioxide} \tn 
% Row Count 10 (+ 3)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{3) {\bf{Avogadro's constant}} describes that {\bf{6.022 x 10\textasciicircum{}23\textasciicircum{} atoms}} of sulfur react with {\bf{6.022 x 10\textasciicircum{}23\textasciicircum{} molecules}} of oxygen forming {\bf{6.022 x 10\textasciicircum{}23\textasciicircum{}  molecules}} of sulfur dioxide} \tn 
% Row Count 14 (+ 4)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{4) The {\bf{Molar Masses}} of the {\bf{reactants}} and {\bf{products}} allow us to say that {\bf{32.06 grams}} of sulfur react with {\bf{32.00 grams}} of oxygen to produce {\bf{64.06 grams}} of sulfur dioxide} \tn 
% Row Count 18 (+ 4)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{8.4cm}}{\bf\textcolor{white}{{\bf{General Rules for Balancing Equations}}}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{First attempts at balancing equations may not work. Try a different approach starting with a different element.} \tn 
% Row Count 3 (+ 3)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{Balance pure elements last (O2, H2, N2)} \tn 
% Row Count 4 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{Do not break up polyatomic ions (SO4\textasciicircum{}2\textasciicircum{}\textasciicircum{}-\textasciicircum{})} \tn 
% Row Count 5 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{x{4 cm} x{4 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{8.4cm}}{\bf\textcolor{white}{{\bf{4-Step Method for Writing Balanced Equations}}}}  \tn
% Row 0
\SetRowColor{LightBackground}
{\bf{Element}} & {\bf{Sulfur}} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{2}{x{8.4cm}}{{\bf{1) Write a preliminary expression containing a single particle (atom, molecule, or formula unit) of each reactant and product with a reaction arrow separating reactants from products. Include phase symbols indicating physical states.}}} \tn 
% Row Count 6 (+ 5)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{8.4cm}}{SO2(g) + O2(g) -\textgreater{} SO3(g)} \tn 
% Row Count 7 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{2}{x{8.4cm}}{{\bf{2) Check whether the expression is balanced by counting the atoms of each element on each side of the reaction arrow.}}} \tn 
% Row Count 10 (+ 3)
% Row 4
\SetRowColor{LightBackground}
Reactant Side & 1 \tn 
% Row Count 11 (+ 1)
% Row 5
\SetRowColor{white}
Product Side & 1 \tn 
% Row Count 12 (+ 1)
% Row 6
\SetRowColor{LightBackground}
Balanced? & yes \tn 
% Row Count 13 (+ 1)
% Row 7
\SetRowColor{white}
{\bf{Element}} & {\bf{Oxygen}} \tn 
% Row Count 14 (+ 1)
% Row 8
\SetRowColor{LightBackground}
Reactant Side & 2+2 = 4 \tn 
% Row Count 15 (+ 1)
% Row 9
\SetRowColor{white}
Product Side & 3 \tn 
% Row Count 16 (+ 1)
% Row 10
\SetRowColor{LightBackground}
Balanced? & no \tn 
% Row Count 17 (+ 1)
% Row 11
\SetRowColor{white}
{\bf{3) Choose an element that appears in only one reactant and one product and balance it first.}} & The only element that occurs only once on each side of the reaction arrow in this equation is sulfur, but it is already balanced, so this step can be skipped. \tn 
% Row Count 25 (+ 8)
% Row 12
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{8.4cm}}{{\bf{4) Choose coefficients for the other substances os that the number of atoms for each element is the same on both sides of the reaction arrow.}}} \tn 
% Row Count 28 (+ 3)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{8.4cm}}{\bf\textcolor{white}{Reaction Stoichiometry}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{{\bf{Ratio of Coefficients in a Chemical Reaction}} {\bf{(Mole Ratio)}}} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{* specify the relative amounts in molecules or moles of each of the substances involved in the reaction} \tn 
% Row Count 5 (+ 3)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{* act as a conversion factor between the amount in moles/molecules of the reactants and products} \tn 
% Row Count 7 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{* can be used to determine how much of one reactant is needed to completely react with another quantity of the other reactant} \tn 
% Row Count 10 (+ 3)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{8.4cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{8.4cm}}{\bf\textcolor{white}{Example Ratio of Coefficients}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{if 22.0 moles of C8H18 are burned, how many moles of CO2 form?} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{8.4cm}}{Stoichiometric Ratio} \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{8.4cm}}{22.0 mol C8H18 x 16 mol CO2/2 mol C8H18 = 176 mol CO2} \tn 
% Row Count 5 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}