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% Document Info
\author{So Ty (pastel-galaxies)}
\pdfinfo{
  /Title (kinematics.pdf)
  /Creator (Cheatography)
  /Author (So Ty (pastel-galaxies))
  /Subject (Kinematics Cheat Sheet)
}

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\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
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    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Kinematics Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{So Ty (pastel-galaxies)} via \textcolor{DarkBackground}{\uline{cheatography.com/51952/cs/14184/}}}
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\noindent
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}So Ty (pastel-galaxies) \\
  \uline{cheatography.com/pastel-galaxies} \\
  \end{tabulary}
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 9th January, 2018.\\
   Page {\thepage} of \pageref{LastPage}.
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Sponsor}}  \\
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  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
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\end{multicols}}




\begin{document}
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\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{X}
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Kinematics}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{{\bf{Kinematics}} is the collective name for the unit that covers acceleration, velocity, displacement, and time and how they relate to each other. It's important to understand the formulas in this unit because they will come back in later units, such as force and work.% Row Count 6 (+ 6)
} \tn 
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\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{1.8308 cm} x{1.8308 cm} p{0.9154 cm} }
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\mymulticolumn{3}{x{5.377cm}}{\bf\textcolor{white}{Measurement Review}}  \tn
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Acceleration & a & m/s\textasciicircum{}2\textasciicircum{} \tn 
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Velocity & V\textasciicircum{}F\textasciicircum{} or V\textasciicircum{}I\textasciicircum{} & m/s \tn 
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Displacement & Δx & m \tn 
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Time & t & s \tn 
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\begin{tabularx}{5.377cm}{X}
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Speed, Velocity and Acceleration}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{{\bf{Speed}}, measured in meters/second, can be found with the formula: \newline % Row Count 2 (+ 2)
{\emph{distance / time}} \newline % Row Count 3 (+ 1)
{\bf{Velocity}}, also measured in meters/second, can be found with the formula: \newline % Row Count 5 (+ 2)
{\emph{displacement / time}}, or Δx / Δt. \newline % Row Count 6 (+ 1)
{\bf{Acceleration}}, measured in meters/second\textasciicircum{}2\textasciicircum{}, can be found with the formula: \newline % Row Count 8 (+ 2)
{\emph{(final velocity - initial velocity) / (final time - initial time)}}, or (V\textasciicircum{}F\textasciicircum{} - V\textasciicircum{}I\textasciicircum{}) / (T\textasciicircum{}F\textasciicircum{} - T\textasciicircum{}I\textasciicircum{}) \newline % Row Count 11 (+ 3)
{\bf{Time}}, measured in seconds, is generally given to you.% Row Count 13 (+ 2)
} \tn 
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\mymulticolumn{1}{x{5.377cm}}{{\emph{T\textasciicircum{}I\textasciicircum{} is usually, but not always, zero.}}}  \tn 
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\begin{tabularx}{5.377cm}{x{3.58344 cm} x{1.39356 cm} }
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\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{The Four Formulas}}  \tn
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{\bf{Formula:}} & {\bf{Missing:}} \tn 
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Δx = V\textasciicircum{}I\textasciicircum{}t + $\frac{1}{2}$ at\textasciicircum{}2\textasciicircum{} & V\textasciicircum{}F\textasciicircum{} \tn 
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\SetRowColor{LightBackground}
V\textasciicircum{}F\textasciicircum{} = V\textasciicircum{}I\textasciicircum{} + at & Δx \tn 
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Δx = (V\textasciicircum{}F\textasciicircum{} + V\textasciicircum{}I\textasciicircum{} / 2) × t & a \tn 
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Δx = (V\textasciicircum{}F\textasciicircum{}\textasciicircum{}2\textasciicircum{} - V\textasciicircum{}I\textasciicircum{}\textasciicircum{}2\textasciicircum{}) / 2a) & t \tn 
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\mymulticolumn{2}{x{5.377cm}}{Every kinematics problem will give you 3 of the 5 variables and ask you to solve for 1 variable. The fifth variable doesn't matter - use the formula {\bf{without}} that variable (if the problem doesn't mention a, use the formula without a in it.)}  \tn 
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\begin{tabularx}{5.377cm}{X}
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Example Problem}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{{\emph{A worker drops a wrench from the top of a tower 80 m tall. What is the velocity when the wrench hits the ground?}} \newline % Row Count 3 (+ 3)
In the context of this problem, we are told that {\emph{Δx = 80 m}}. We know that {\emph{V\textasciicircum{}I\textasciicircum{} = 0 m/s}} because at the beginning of the problem, the wrench wasn't moving (the worker was holding it. And we can assume that {\emph{acceleration is 9.8 m/s\textasciicircum{}2\textasciicircum{}}} because {\bf{gravity}} is taking effect. \newline % Row Count 9 (+ 6)
This leaves us with {\bf{V\textasciicircum{}F\textasciicircum{}}} and {\bf{t}}. Since the question is asking us for final velocity, we know that {\bf{t}} isn't important to this problem - therefore, choose the kinematic equation without the {\bf{t}} in it to solve the problem.% Row Count 14 (+ 5)
} \tn 
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\mymulticolumn{1}{x{5.377cm}}{The equation without {\bf{t}} in it is {\bf{Δx = (V\textasciicircum{}F\textasciicircum{}\textasciicircum{}2\textasciicircum{} + V\textasciicircum{}I\textasciicircum{}\textasciicircum{}2\textasciicircum{}) / 2a.}} Then, all that's left to do is to plug in all the variables and solve for V\textasciicircum{}F\textasciicircum{}! \newline  \newline The answer to this problem should be {\emph{39.60 m/s.}}}  \tn 
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% That's all folks
\end{multicols*}

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