\documentclass[10pt,a4paper]{article} % Packages \usepackage{fancyhdr} % For header and footer \usepackage{multicol} % Allows multicols in tables \usepackage{tabularx} % Intelligent column widths \usepackage{tabulary} % Used in header and footer \usepackage{hhline} % Border under tables \usepackage{graphicx} % For images \usepackage{xcolor} % For hex colours %\usepackage[utf8x]{inputenc} % For unicode character support \usepackage[T1]{fontenc} % Without this we get weird character replacements \usepackage{colortbl} % For coloured tables \usepackage{setspace} % For line height \usepackage{lastpage} % Needed for total page number \usepackage{seqsplit} % Splits long words. %\usepackage{opensans} % Can't make this work so far. Shame. Would be lovely. \usepackage[normalem]{ulem} % For underlining links % Most of the following are not required for the majority % of cheat sheets but are needed for some symbol support. \usepackage{amsmath} % Symbols \usepackage{MnSymbol} % Symbols \usepackage{wasysym} % Symbols %\usepackage[english,german,french,spanish,italian]{babel} % Languages % Document Info \author{pablocdch} \pdfinfo{ /Title (algebra-calculus-i-and-ii.pdf) /Creator (Cheatography) /Author (pablocdch) /Subject (Algebra, Calculus I \& II Cheat Sheet) } % Lengths and widths \addtolength{\textwidth}{6cm} \addtolength{\textheight}{-1cm} \addtolength{\hoffset}{-3cm} \addtolength{\voffset}{-2cm} \setlength{\tabcolsep}{0.2cm} % Space between columns \setlength{\headsep}{-12pt} % Reduce space between header and content \setlength{\headheight}{85pt} % If less, LaTeX automatically increases it \renewcommand{\footrulewidth}{0pt} % Remove footer line \renewcommand{\headrulewidth}{0pt} % Remove header line \renewcommand{\seqinsert}{\ifmmode\allowbreak\else\-\fi} % Hyphens in seqsplit % This two commands together give roughly % the right line height in the tables \renewcommand{\arraystretch}{1.3} \onehalfspacing % Commands \newcommand{\SetRowColor}[1]{\noalign{\gdef\RowColorName{#1}}\rowcolor{\RowColorName}} % Shortcut for row colour \newcommand{\mymulticolumn}[3]{\multicolumn{#1}{>{\columncolor{\RowColorName}}#2}{#3}} % For coloured multi-cols \newcolumntype{x}[1]{>{\raggedright}p{#1}} % New column types for ragged-right paragraph columns \newcommand{\tn}{\tabularnewline} % Required as custom column type in use % Font and Colours \definecolor{HeadBackground}{HTML}{333333} \definecolor{FootBackground}{HTML}{666666} \definecolor{TextColor}{HTML}{333333} \definecolor{DarkBackground}{HTML}{4D65FF} \definecolor{LightBackground}{HTML}{F3F5FF} \renewcommand{\familydefault}{\sfdefault} \color{TextColor} % Header and Footer \pagestyle{fancy} \fancyhead{} % Set header to blank \fancyfoot{} % Set footer to blank \fancyhead[L]{ \noindent \begin{multicols}{3} \begin{tabulary}{5.8cm}{C} \SetRowColor{DarkBackground} \vspace{-7pt} {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}} } \end{tabulary} \columnbreak \begin{tabulary}{11cm}{L} \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Algebra, Calculus I \& II Cheat Sheet}}}} \\ \normalsize{by \textcolor{DarkBackground}{pablocdch} via \textcolor{DarkBackground}{\uline{cheatography.com/30131/cs/8927/}}} \end{tabulary} \end{multicols}} \fancyfoot[L]{ \footnotesize \noindent \begin{multicols}{3} \begin{tabulary}{5.8cm}{LL} \SetRowColor{FootBackground} \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}} \\ \vspace{-2pt}pablocdch \\ \uline{cheatography.com/pablocdch} \\ \end{tabulary} \vfill \columnbreak \begin{tabulary}{5.8cm}{L} \SetRowColor{FootBackground} \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}} \\ \vspace{-2pt}Not Yet Published.\\ Updated 9th January, 2017.\\ Page {\thepage} of \pageref{LastPage}. \end{tabulary} \vfill \columnbreak \begin{tabulary}{5.8cm}{L} \SetRowColor{FootBackground} \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Sponsor}} \\ \SetRowColor{white} \vspace{-5pt} %\includegraphics[width=48px,height=48px]{dave.jpeg} Measure your website readability!\\ www.readability-score.com \end{tabulary} \end{multicols}} \begin{document} \raggedright \raggedcolumns % Set font size to small. Switch to any value % from this page to resize cheat sheet text: % www.emerson.emory.edu/services/latex/latex_169.html \footnotesize % Small font. \begin{multicols*}{3} \begin{tabularx}{5.377cm}{x{2.04057 cm} x{2.93643 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Derivatives}} \tn % Row 0 \SetRowColor{LightBackground} Expression & Derivative \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} f(x)=k & f'(x)=0 \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} f(x)=x & f'(x)=1 \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} f(x)=x\textasciicircum{}a\textasciicircum{} & f'(x)=ax\textasciicircum{}a-1\textasciicircum{} \tn % Row Count 4 (+ 1) % Row 4 \SetRowColor{LightBackground} f(x)=a\textasciicircum{}x\textasciicircum{} & f'(x)=a\textasciicircum{}x\textasciicircum{} lna \tn % Row Count 5 (+ 1) % Row 5 \SetRowColor{white} f(x)=kx & f'(x)=k \tn % Row Count 6 (+ 1) % Row 6 \SetRowColor{LightBackground} f(x)=1/x & f'(x)=-1/x\textasciicircum{}2\textasciicircum{} \tn % Row Count 7 (+ 1) % Row 7 \SetRowColor{white} f(x)=ln x & f'(x)=1/x \tn % Row Count 8 (+ 1) % Row 8 \SetRowColor{LightBackground} f(x)=e\textasciicircum{}u\textasciicircum{} & f'(x)=u'.e\textasciicircum{}u\textasciicircum{} \tn % Row Count 9 (+ 1) % Row 9 \SetRowColor{white} f(x)=logaX & f'(x)=1/x lna \tn % Row Count 10 (+ 1) % Row 10 \SetRowColor{LightBackground} f(x)=sen(x) & f'(x)=cos(x) \tn % Row Count 11 (+ 1) % Row 11 \SetRowColor{white} f(x)=sec(x) & f'(x)=sec(x).tan(x) \tn % Row Count 12 (+ 1) % Row 12 \SetRowColor{LightBackground} f(x)=arcsen(x) & f'(x)=1/√1-x\textasciicircum{}2\textasciicircum{} \tn % Row Count 13 (+ 1) % Row 13 \SetRowColor{white} f(x)=cos(x) & f'(x)=-sen(x) \tn % Row Count 14 (+ 1) % Row 14 \SetRowColor{LightBackground} f(x)=csc(x) & f'(x)=-csc(x).ctg(x) \tn % Row Count 15 (+ 1) % Row 15 \SetRowColor{white} f(x)=arccos(x) & f'(x)=-1/√1-x\textasciicircum{}2\textasciicircum{} \tn % Row Count 16 (+ 1) % Row 16 \SetRowColor{LightBackground} f(x)=tan(x) & f'(x)=sec\textasciicircum{}2\textasciicircum{}(x) \tn % Row Count 17 (+ 1) % Row 17 \SetRowColor{white} f(x)=ctg(x) & f'(x)=-csc\textasciicircum{}2\textasciicircum{}(x) \tn % Row Count 18 (+ 1) % Row 18 \SetRowColor{LightBackground} f(x)=arctan(x) & f'(x)=1/1+x\textasciicircum{}2\textasciicircum{} \tn % Row Count 19 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{x{2.04057 cm} x{2.93643 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Integrals}} \tn % Row 0 \SetRowColor{LightBackground} ∫x\textasciicircum{}k\textasciicircum{}dx & (x\textasciicircum{}k+1\textasciicircum{})/(k+1) + C \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} ∫x\textasciicircum{}-1\textasciicircum{}dx & ln|x| + C \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} ∫dx & x + C \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} ∫kF(x)dx & k∫F(x)dx \tn % Row Count 4 (+ 1) % Row 4 \SetRowColor{LightBackground} ∫{[}F(x)±∫G(x){]} & ∫F(x)dx ± ∫G(x)dx \tn % Row Count 6 (+ 2) % Row 5 \SetRowColor{white} ∫e\textasciicircum{}kx\textasciicircum{}dx & (1/k)e\textasciicircum{}kx\textasciicircum{} + C \tn % Row Count 7 (+ 1) % Row 6 \SetRowColor{LightBackground} ∫a\textasciicircum{}kx\textasciicircum{}dx & a\textasciicircum{}kx\textasciicircum{}/{[}kLn(a){]} + C \tn % Row Count 8 (+ 1) % Row 7 \SetRowColor{white} ∫sen(kx) dx & -(1/k) cos(kx) + C \tn % Row Count 9 (+ 1) % Row 8 \SetRowColor{LightBackground} ∫cos(kx) dx & 1/k sen(kx) + C \tn % Row Count 10 (+ 1) % Row 9 \SetRowColor{white} ∫sec(kx) dx & 1/k(Ln|sec(kx) + tan(kx)|) + C \tn % Row Count 12 (+ 2) % Row 10 \SetRowColor{LightBackground} ∫Tan(kx) dx & -(1/k) Ln|cos(kx)| + C \tn % Row Count 13 (+ 1) % Row 11 \SetRowColor{white} ∫csc(kx) dx & 1/k Ln |csc(kx) - cot(kx)| + C \tn % Row Count 15 (+ 2) % Row 12 \SetRowColor{LightBackground} ∫cot(kx) dx & 1/k Ln |sen(kx)| + C \tn % Row Count 16 (+ 1) % Row 13 \SetRowColor{white} ∫sec(kx) dx & 1/k sec(kx) + C \tn % Row Count 17 (+ 1) % Row 14 \SetRowColor{LightBackground} ∫csc(kx) cot(kx) dx & -1/k csc(kx) + C \tn % Row Count 19 (+ 2) % Row 15 \SetRowColor{white} ∫sex\textasciicircum{}2\textasciicircum{}(kx) dx & 1/k tan(kx) + C \tn % Row Count 20 (+ 1) % Row 16 \SetRowColor{LightBackground} ∫csc\textasciicircum{}2\textasciicircum{}(kx) dx & -1/k cot(kx) + C \tn % Row Count 21 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Quadratic formula}} \tn \SetRowColor{LightBackground} \mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/pablocdch_1472097554_Quadratic_formula.svg.png}}} \tn \hhline{>{\arrayrulecolor{DarkBackground}}-} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{x{1.39356 cm} x{3.58344 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Factoring}} \tn % Row 0 \SetRowColor{LightBackground} (a + b)\textasciicircum{}2\textasciicircum{} & a\textasciicircum{}2\textasciicircum{} + 2ab + b\textasciicircum{}2\textasciicircum{} \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} (a - b)\textasciicircum{}2\textasciicircum{} & a\textasciicircum{}2\textasciicircum{} - 2ab + b\textasciicircum{}2\textasciicircum{} \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} a\textasciicircum{}2\textasciicircum{} - b\textasciicircum{}2\textasciicircum{} & (a - b) (a + b) \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} (a + b)\textasciicircum{}3\textasciicircum{} & a\textasciicircum{}3\textasciicircum{} + 3a\textasciicircum{}2\textasciicircum{}b + 3ab\textasciicircum{}2\textasciicircum{} + b\textasciicircum{}3\textasciicircum{} \tn % Row Count 5 (+ 2) % Row 4 \SetRowColor{LightBackground} (a - b)\textasciicircum{}3\textasciicircum{} & a\textasciicircum{}3\textasciicircum{} - 3a\textasciicircum{}2\textasciicircum{}b + 3ab\textasciicircum{}2\textasciicircum{} - b\textasciicircum{}3\textasciicircum{} \tn % Row Count 7 (+ 2) % Row 5 \SetRowColor{white} a\textasciicircum{}3\textasciicircum{} - b\textasciicircum{}3\textasciicircum{} & (a - b)\textasciicircum{}3 + 3ab (a - b) \tn % Row Count 8 (+ 1) % Row 6 \SetRowColor{LightBackground} a\textasciicircum{}3\textasciicircum{} + b\textasciicircum{}3\textasciicircum{} & (a + b)\textasciicircum{}3\textasciicircum{} - 3a b (a + b) \tn % Row Count 9 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Factoring}} \tn \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{Given x\textasciicircum{}2+ax+b=0, then you have to find two numbers that when {\bf{multiplied }}give you {\bf{B}} and {\bf{added}} give you {\bf{a}}. \newline % Row Count 3 (+ 3) {\bf{Example:}} \newline % Row Count 4 (+ 1) x\textasciicircum{}2+4x+3, turns into: (x+3)(x+1)% Row Count 5 (+ 1) } \tn \hhline{>{\arrayrulecolor{DarkBackground}}-} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{p{1.54287 cm} x{3.43413 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Absolute value propertie}} \tn % Row 0 \SetRowColor{LightBackground} |x|\textgreater{}a & x\textgreater{}a or a\textless{}-a \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} |x|\textless{}a & -a\textless{}x\textless{}a \tn % Row Count 2 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{p{3.08574 cm} p{1.89126 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Divisions with 0}} \tn % Row 0 \SetRowColor{LightBackground} 0/n & 0 \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} n/∞ & 0 \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} n/0 & ∞ \tn % Row Count 3 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{x{2.04057 cm} x{2.93643 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Logs properties}} \tn % Row 0 \SetRowColor{LightBackground} logaB\textasciicircum{}n\textasciicircum{} & nlogaB \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} logaA=lne & 1 \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} loga1=ln1 & 0 \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} loga(m.n) & logaM + logaN \tn % Row Count 4 (+ 1) % Row 4 \SetRowColor{LightBackground} loga(m/n) & logaM - logaM \tn % Row Count 5 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{x{2.18988 cm} x{2.78712 cm} } \SetRowColor{DarkBackground} \mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Exponential properties}} \tn % Row 0 \SetRowColor{LightBackground} a\textasciicircum{}0\textasciicircum{} & 1 \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} a\textasciicircum{}1\textasciicircum{} & a \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} a\textasciicircum{}m\textasciicircum{} . a\textasciicircum{}n\textasciicircum{} & a\textasciicircum{}m+n\textasciicircum{} \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} a\textasciicircum{}m\textasciicircum{} / a\textasciicircum{}n\textasciicircum{} & a\textasciicircum{}m-n\textasciicircum{} \tn % Row Count 4 (+ 1) % Row 4 \SetRowColor{LightBackground} (a.b)\textasciicircum{}n\textasciicircum{} & a\textasciicircum{}n\textasciicircum{} . b\textasciicircum{}n\textasciicircum{} \tn % Row Count 5 (+ 1) % Row 5 \SetRowColor{white} (a/b)\textasciicircum{}n\textasciicircum{} & a\textasciicircum{}n\textasciicircum{}/b\textasciicircum{}n\textasciicircum{} \tn % Row Count 6 (+ 1) % Row 6 \SetRowColor{LightBackground} (a\textasciicircum{}m\textasciicircum{})\textasciicircum{}n\textasciicircum{} & a\textasciicircum{}m.n\textasciicircum{} \tn % Row Count 7 (+ 1) % Row 7 \SetRowColor{white} a\textasciicircum{}n/m\textasciicircum{} & raiz m de a\textasciicircum{}n\textasciicircum{} \tn % Row Count 8 (+ 1) % Row 8 \SetRowColor{LightBackground} a\textasciicircum{}-1\textasciicircum{} & 1/a \tn % Row Count 9 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}--} \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{5.377cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Trigonometrical identities}} \tn % Row 0 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sen$^{\textrm{2}}$ α + cos$^{\textrm{2}}$ α = 1} \tn % Row Count 1 (+ 1) % Row 1 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{sec$^{\textrm{2}}$ α = 1 + tg$^{\textrm{2}}$ α} \tn % Row Count 2 (+ 1) % Row 2 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{cosec$^{\textrm{2}}$ α = 1 + cotg$^{\textrm{2}}$ α} \tn % Row Count 3 (+ 1) % Row 3 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{tan α = senα/cosα} \tn % Row Count 4 (+ 1) % Row 4 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{tan$^{\textrm{2}}$ α +1 = sec$^{\textrm{2}}$ α} \tn % Row Count 5 (+ 1) % Row 5 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cot$^{\textrm{2}}$ α +1 = csc$^{\textrm{2}}$ α} \tn % Row Count 6 (+ 1) % Row 6 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin(x + y) = sin(x) cos(y) + cos(x) sin(y)} \tn % Row Count 7 (+ 1) % Row 7 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cos(x + y) = cos(x) cos(y) − sin(x) sin(y)} \tn % Row Count 8 (+ 1) % Row 8 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{tan(x + y) = (tan(x) + tan(y))/(1 − tan(x) tan(y))} \tn % Row Count 10 (+ 2) % Row 9 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{sin(x − y) = sin(x) cos(y) − cos(x) sin(y)} \tn % Row Count 11 (+ 1) % Row 10 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{cos(x − y) = cos(x) cos(y) + sin(x) sin(y)} \tn % Row Count 12 (+ 1) % Row 11 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{tan(x − y) = (tan(x) − tan(y))/(1 + tan(x) tan(y))} \tn % Row Count 14 (+ 2) % Row 12 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin (2 x) = 2 sin (x) cos (x)} \tn % Row Count 15 (+ 1) % Row 13 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cos (2 x) = cos2 (x) − sin2 (x)} \tn % Row Count 16 (+ 1) % Row 14 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{cos (2 x) = 2 cos2 (x) − 1} \tn % Row Count 17 (+ 1) % Row 15 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{tan (2 x) = (2 tan (x))/(1 − tan2 (x))} \tn % Row Count 18 (+ 1) % Row 16 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin2 (x) = 1/2 (1 − cos (2 x))} \tn % Row Count 19 (+ 1) % Row 17 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cos2 (x) = 1/2 (1 + cos (2 x))} \tn % Row Count 20 (+ 1) % Row 18 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin (x) cos (x) = 1/2 sin (2 x)} \tn % Row Count 21 (+ 1) % Row 19 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{sin (x) sin (y) = 1/2 (cos (x − y) − cos (x + y))} \tn % Row Count 23 (+ 2) % Row 20 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin (x) cos (y) = 1/2 (sin (x − y) + sin (x + y))} \tn % Row Count 25 (+ 2) % Row 21 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cos (x) cos (y) = 1/2 (cos (x − y) + cos (x + y))} \tn % Row Count 27 (+ 2) % Row 22 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{csc(x) = 1/sin(x)} \tn % Row Count 28 (+ 1) % Row 23 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{sec(x) = 1/cos(x)} \tn % Row Count 29 (+ 1) % Row 24 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{cot(x) = cos(x)/tan(x)} \tn % Row Count 30 (+ 1) \end{tabularx} \par\addvspace{1.3em} \vfill \columnbreak \begin{tabularx}{5.377cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Trigonometrical identities (cont)}} \tn % Row 25 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{sin(−x) = − sin(x)} \tn % Row Count 1 (+ 1) % Row 26 \SetRowColor{white} \mymulticolumn{1}{x{5.377cm}}{cos(−x) = cos(x)} \tn % Row Count 2 (+ 1) % Row 27 \SetRowColor{LightBackground} \mymulticolumn{1}{x{5.377cm}}{tan(−x) = − tan(x)} \tn % Row Count 3 (+ 1) \hhline{>{\arrayrulecolor{DarkBackground}}-} \end{tabularx} \par\addvspace{1.3em} % That's all folks \end{multicols*} \end{document}