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%\usepackage{opensans}          % Can't make this work so far. Shame. Would be lovely.
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% Most of the following are not required for the majority
% of cheat sheets but are needed for some symbol support.
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% Document Info
\author{Mudassir Khan (mvdassir\_)}
\pdfinfo{
  /Title (gaseous-state.pdf)
  /Creator (Cheatography)
  /Author (Mudassir Khan (mvdassir\_))
  /Subject (Gaseous State Cheat Sheet)
}

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% Header and Footer
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\fancyhead[L]{
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
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    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\columnbreak
\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Gaseous State Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{Mudassir Khan (mvdassir\_)} via \textcolor{DarkBackground}{\uline{cheatography.com/160173/cs/33710/}}}
\end{tabulary}
\end{multicols}}

\fancyfoot[L]{ \footnotesize
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{LL}
  \SetRowColor{FootBackground}
  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}Mudassir Khan (mvdassir\_) \\
  \uline{cheatography.com/mvdassir} \\
  \end{tabulary}
\vfill
\columnbreak
\begin{tabulary}{5.8cm}{L}
  \SetRowColor{FootBackground}
  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Published 18th August, 2022.\\
   Updated 18th August, 2022.\\
   Page {\thepage} of \pageref{LastPage}.
\end{tabulary}
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  \vspace{-5pt}
  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
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\begin{document}
\raggedright
\raggedcolumns

% Set font size to small. Switch to any value
% from this page to resize cheat sheet text:
% www.emerson.emory.edu/services/latex/latex_169.html
\footnotesize % Small font.

\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Conversions}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{{\bf{Volume}} \newline % Row Count 1 (+ 1)
1 Litre= 10$^{\textrm{3}}$ mL= 10$^{\textrm{3}}$ cm$^{\textrm{3}}$= 10⁻$^{\textrm{3}}$ m$^{\textrm{3}}$= 1 dm$^{\textrm{3}}$ \newline % Row Count 2 (+ 1)
{\bf{Pressure}} \newline % Row Count 3 (+ 1)
1 atm= 76 cm of Hg= 760 mm of Hg= 760 torr \newline % Row Count 4 (+ 1)
1 atm= 1.01*10$^{\textrm{5}}$ Nm$^{\textrm{2}}$ \newline % Row Count 5 (+ 1)
1 atm= 1.01*10$^{\textrm{5}}$ Pa \newline % Row Count 6 (+ 1)
1 bar= 0.9862 atm≈ 1 atm% Row Count 7 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{mL= milli-litre  \newline cm= centimeter  \newline m= meter  \newline dm= decimeter  \newline atm= atmosphere  \newline N= Newton  \newline Pa= Pascals}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Boyle's Law}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660827862_Screenshot 2022-08-18 183321.jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{According to Boyle's law, \newline V ∝ P⁻$^{\textrm{1}}$ \newline or, PV = constant @particular temperature. \newline or, P₁V₁=P₂V₂}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Charles' Law}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660831667_charles laq.jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{According to Charles' Law,  \newline V ∝ T @constant Pressure \newline therefore, V₁/T₁ = V₂/T₂ \newline or, V₁T₂ = V₂T₁}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Gay-Lussac's Law}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660832203_lussacs law.jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{According to Lussac's law, \newline P ∝ T \newline or, PT⁻$^{\textrm{1}}$ = constant @constant volume \newline P₁T₂ = P₂T₁}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Ideal Gas Equation}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{PV=nRT \newline % Row Count 1 (+ 1)
or, PVT⁻$^{\textrm{1}}$ = constant = nR \newline % Row Count 2 (+ 1)
R= Universal Gas Constant% Row Count 3 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Universal Gas Constant}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{{[}R{]} = Lit atm K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$ = work done per Kelvin per mole \newline % Row Count 2 (+ 2)
R= 0.0821 Lit atm K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$ \newline % Row Count 3 (+ 1)
R= 8.314 J K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$ = 8.314 Pa cm$^{\textrm{3}}$ K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$ \newline % Row Count 5 (+ 2)
R= 1.987 cal K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$ \newline % Row Count 6 (+ 1)
R= 5.189* 10\textasciicircum{}19\textasciicircum{} eV K⁻$^{\textrm{1}}$ mol⁻$^{\textrm{1}}$% Row Count 7 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
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\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Dalton's Law of Partial Pressure}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{According to Dalton's Law of Partial Pressure, \newline % Row Count 1 (+ 1)
P =  \seqsplit{P₁+P₂+P₃+.....+Pₙ} = ΣPₙ \newline % Row Count 2 (+ 1)
Where P is the total pressure and P₁, P₂, P₃... are the partial pressures of gases 1, 2, 3 and so on. \newline % Row Count 5 (+ 3)
 P₁= P*x₁ \newline % Row Count 6 (+ 1)
where x₁ is the mole fraction of gas 1.% Row Count 7 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
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\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Graham's Law of Diffusion}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660834067_combine_images (2).jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{r= rate of diffusion \newline M= molar mass of given gas \newline d= density of given gas \newline n= number of moles of given gas}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Velocity of Gas Particles}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660835397_combine_images (3).jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{α:v:u = 1 : 1.128 : 1.224}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Kinetic Energy}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660844052_combine_images.png}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{k = Boltzmann Constant = 1.380649 × 10\textasciicircum{}−23\textasciicircum{} joule per kelvin}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Van der waal's Equation}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660842198_combine_images.jpg}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Molecular Collision}}  \tn
\SetRowColor{LightBackground}
\mymulticolumn{1}{p{5.377cm}}{\vspace{1px}\centerline{\includegraphics[width=5.1cm]{/web/www.cheatography.com/public/uploads/mvdassir_1660845891_combine_images (2).png}}} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}