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% Document Info
\author{Mudassir Khan (mvdassir\_)}
\pdfinfo{
  /Title (basics-of-chemistry.pdf)
  /Creator (Cheatography)
  /Author (Mudassir Khan (mvdassir\_))
  /Subject (Basics of Chemistry Cheat Sheet)
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\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
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    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Basics of Chemistry Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{Mudassir Khan (mvdassir\_)} via \textcolor{DarkBackground}{\uline{cheatography.com/160173/cs/33709/}}}
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\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{LL}
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}Mudassir Khan (mvdassir\_) \\
  \uline{cheatography.com/mvdassir} \\
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Published 18th August, 2022.\\
   Updated 18th August, 2022.\\
   Page {\thepage} of \pageref{LastPage}.
\end{tabulary}
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  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
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\end{multicols}}




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\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{X}
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Mole}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{In the field of chemistry, a mole is defined as the amount of a substance that contains exactly 6.02214076 * 10\textasciicircum{}23\textasciicircum{} 'elementary entities' of the given substance.% Row Count 4 (+ 4)
} \tn 
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Number of Moles}}  \tn
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\begin{tabularx}{5.377cm}{x{1.64772 cm} x{1.78503 cm} x{1.14425 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{3}{x{5.377cm}}{\bf\textcolor{white}{STP vs NTP}}  \tn
% Row 0
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Properties & STP & NTP \tn 
% Row Count 1 (+ 1)
% Row 1
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Temperature (in Kelvin) & 273.16 K ≈ 273 K & 293.16K ≈ 293 K \tn 
% Row Count 3 (+ 2)
% Row 2
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Temperature (in Celsius) & 0\textasciicircum{}o\textasciicircum{}C & 20\textasciicircum{}o\textasciicircum{}C \tn 
% Row Count 5 (+ 2)
% Row 3
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Pressure & 1 bar= 0.9862 atm≈ 1 atm & 1 atm \tn 
% Row Count 7 (+ 2)
% Row 4
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Pressure (in Nm\textasciicircum{}2\textasciicircum{}) & 10\textasciicircum{}5\textasciicircum{} Nm\textasciicircum{}2\textasciicircum{} & 1.01*10\textasciicircum{}5\textasciicircum{} Nm\textasciicircum{}2\textasciicircum{} \tn 
% Row Count 9 (+ 2)
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\mymulticolumn{3}{x{5.377cm}}{K= Kelvin↔(temperature) \newline \textasciicircum{}o\textasciicircum{}C= Degree Celsius↔(temperature) \newline atm= atmosphere↔(pressure) \newline Nm\textasciicircum{}2\textasciicircum{}= Newton*(meter)\textasciicircum{}2\textasciicircum{}↔(pressure)}  \tn 
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Percentage Composition of an Element}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{\{\{bt\}\}n= Number of atoms of the element in one molecule of the compound}  \tn 
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Temperature Conversions}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{\textasciicircum{}o\textasciicircum{}F= Degree Fahrenheit \newline \textasciicircum{}o\textasciicircum{}C= Degree Celsius \newline K= Degree Kelvin}  \tn 
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\mymulticolumn{3}{x{5.377cm}}{\bf\textcolor{white}{Laws of Chemistry}}  \tn
% Row 0
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{\bf{LAWS}} & {\bf{SCIENTISTS}} & {\bf{DATE}} \tn 
% Row Count 2 (+ 2)
% Row 1
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1. Law of Conservation of Mass & Antoine Lavoisier & 1744 \tn 
% Row Count 4 (+ 2)
% Row 2
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2. Law of Definite Composition/Proportions & Joseph Proust & 1799 \tn 
% Row Count 6 (+ 2)
% Row 3
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3. Law of Multiple Proportions & John Dalton & 1804 \tn 
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% Row 4
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4. Law of Gaseous volume & Gay Lussac & 1808 \tn 
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\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Conversions}}  \tn
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\mymulticolumn{1}{x{5.377cm}}{{\bf{Volume}} \newline % Row Count 1 (+ 1)
1 Litre= 10$^{\textrm{3}}$ mL= 10$^{\textrm{3}}$ cm$^{\textrm{3}}$= 10⁻$^{\textrm{3}}$ m$^{\textrm{3}}$= 1 dm$^{\textrm{3}}$ \newline % Row Count 2 (+ 1)
{\bf{Pressure}} \newline % Row Count 3 (+ 1)
1 atm= 76 cm of Hg= 760 mm of Hg= 760 torr \newline % Row Count 4 (+ 1)
1 atm= 1.01*10$^{\textrm{5}}$ Nm$^{\textrm{2}}$ \newline % Row Count 5 (+ 1)
1 atm= 1.01*10$^{\textrm{5}}$ Pa \newline % Row Count 6 (+ 1)
1 bar= 0.9862 atm≈ 1 atm% Row Count 7 (+ 1)
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\mymulticolumn{1}{x{5.377cm}}{mL= milli-litre \newline cm= centimeter \newline m= meter \newline dm= decimeter \newline atm= atmosphere \newline N= Newton \newline Pa= Pascals}  \tn 
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\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}