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% Document Info
\author{jash24}
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  /Title (general-chemistry-i-uiuc.pdf)
  /Creator (Cheatography)
  /Author (jash24)
  /Subject (General Chemistry I UIUC Cheat Sheet)
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    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{General Chemistry I UIUC Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{jash24} via \textcolor{DarkBackground}{\uline{cheatography.com/20424/cs/8784/}}}
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}jash24 \\
  \uline{cheatography.com/jash24} \\
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 5th August, 2016.\\
   Page {\thepage} of \pageref{LastPage}.
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  Measure your website readability!\\
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\mymulticolumn{1}{x{3.833cm}}{Electron Geometry = Shape \newline Molecular Geometry = Geometry}  \tn 
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% Row 0
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{\bf{State Function}} & Energy, Entropy, Enthalpy \tn 
% Row Count 2 (+ 2)
% Row 1
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{\bf{Extensive Property}} & Heat of a reaction \tn 
% Row Count 4 (+ 2)
% Row 2
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{\bf{Intensive Property}} & Temperature \tn 
% Row Count 6 (+ 2)
% Row 3
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{\bf{If products are at a higher temp, heat flows out of system}} & Q will be negative \tn 
% Row Count 10 (+ 4)
% Row 4
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{\bf{If the volume increases during the reaction, the system does work}} & W is negative \tn 
% Row Count 14 (+ 4)
% Row 5
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{\bf{Phase Change}} & 7 times more energy needed to convert liquid water to steam than ice to liquid water because of hydrogen bonding. Specific Heat capacity for liquid water is higher than that of ice and steam. \tn 
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{\bf{Formation of a bond}} & Exothermic \tn 
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% Row 1
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{\bf{Breaking of a bond}} & Endothermic \tn 
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{\bf{Triple Bond}} & strongest but shortest \tn 
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% Row 3
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{\bf{Single Bond}} & weakest but longest \tn 
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% Row 4
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{\bf{Periodic Trend}} & As the ions get bigger (down a group) the distance between them does as well and the magnitude of the lattice energy decreases which means that less energy is released when the lattice forms. \tn 
% Row Count 17 (+ 10)
% Row 5
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{\bf{If reaction is reversed, the new equilibrium constant:}} & K' = 1/K \tn 
% Row Count 20 (+ 3)
% Row 6
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{\bf{If reaction is multiplied by m, the new equilibrium constant:}} & K'' = K\textasciicircum{}m \tn 
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% Row 7
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Q\textless{}Ksp & No precipitate; shift right \tn 
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% Row 8
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Q = Ksp & Saturated Solution \tn 
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% Row 9
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Q\textgreater{}Ksp & Precipitate Formed \tn 
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% Row 1
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% That's all folks
\end{multicols*}

\end{document}