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%\usepackage{opensans}          % Can't make this work so far. Shame. Would be lovely.
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% Most of the following are not required for the majority
% of cheat sheets but are needed for some symbol support.
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\usepackage{MnSymbol}           % Symbols
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% Document Info
\author{CyberCube}
\pdfinfo{
  /Title (sch4u-organic-chemistry-cheat-sheet.pdf)
  /Creator (Cheatography)
  /Author (CyberCube)
  /Subject (SCH4U Organic Chemistry Cheat Sheet)
}

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% Header and Footer
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\fancyhead[L]{
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
    \SetRowColor{DarkBackground}
    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
    }
\end{tabulary}
\columnbreak
\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{SCH4U Organic Chemistry Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{CyberCube} via \textcolor{DarkBackground}{\uline{cheatography.com/175012/cs/36770/}}}
\end{tabulary}
\end{multicols}}

\fancyfoot[L]{ \footnotesize
\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{LL}
  \SetRowColor{FootBackground}
  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}CyberCube \\
  \uline{cheatography.com/cybercube} \\
  \end{tabulary}
\vfill
\columnbreak
\begin{tabulary}{5.8cm}{L}
  \SetRowColor{FootBackground}
  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 28th January, 2023.\\
   Page {\thepage} of \pageref{LastPage}.
\end{tabulary}
\vfill
\columnbreak
\begin{tabulary}{5.8cm}{L}
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Sponsor}}  \\
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  \vspace{-5pt}
  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
\end{tabulary}
\end{multicols}}




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% from this page to resize cheat sheet text:
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\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{x{2.24273 cm} x{0.86963 cm} x{1.46464 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{3}{x{5.377cm}}{\bf\textcolor{white}{Root Name/Branch Prefixes}}  \tn
% Row 0
\SetRowColor{LightBackground}
Number of C atoms / branches & Root prefix & Multiplying prefix \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
1 & meth- & mono- \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
2 & eth- & di- \tn 
% Row Count 4 (+ 1)
% Row 3
\SetRowColor{white}
3 & prop- & tri- \tn 
% Row Count 5 (+ 1)
% Row 4
\SetRowColor{LightBackground}
4 & but- & tetra- \tn 
% Row Count 6 (+ 1)
% Row 5
\SetRowColor{white}
5 & pent- & penta- \tn 
% Row Count 7 (+ 1)
% Row 6
\SetRowColor{LightBackground}
6 & hex- & hexa- \tn 
% Row Count 8 (+ 1)
% Row 7
\SetRowColor{white}
7 & hep- & hepta- \tn 
% Row Count 9 (+ 1)
% Row 8
\SetRowColor{LightBackground}
8 & oct- & octa- \tn 
% Row Count 10 (+ 1)
% Row 9
\SetRowColor{white}
9 & non- & nona- \tn 
% Row Count 11 (+ 1)
% Row 10
\SetRowColor{LightBackground}
10 & dec- & deca- \tn 
% Row Count 12 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}---}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{p{2.4885 cm} p{2.4885 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Alkyl Groups}}  \tn
% Row 0
\SetRowColor{LightBackground}
CH3 & methyl \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
C2H5 & ethyl \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
C3H7 & propyk \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
C4H9 & butyl \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
C5H11 & pentyl \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
C6H13 & hexyl \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
C7H15 & heptyl \tn 
% Row Count 7 (+ 1)
% Row 7
\SetRowColor{white}
C8H17 & octyle \tn 
% Row Count 8 (+ 1)
% Row 8
\SetRowColor{LightBackground}
C9H19 & nonyl \tn 
% Row Count 9 (+ 1)
% Row 9
\SetRowColor{white}
C10H21 & decyl \tn 
% Row Count 10 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{p{2.28942 cm} x{2.68758 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{{\bf{Alkanes}}}}  \tn
% Row 0
\SetRowColor{LightBackground}
CH4 & Methane \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
C2H6 & Ethane \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
C3H8 & Propane \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
C4H10 & Butane \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
C5H12 & Pentane \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
C6H14 & Hexane \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
C7H16 & Heptane \tn 
% Row Count 7 (+ 1)
% Row 7
\SetRowColor{white}
C8H18 & Octane \tn 
% Row Count 8 (+ 1)
% Row 8
\SetRowColor{LightBackground}
C9H20 & Nonane \tn 
% Row Count 9 (+ 1)
% Row 9
\SetRowColor{white}
C10H22 & Decane \tn 
% Row Count 10 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{General Formula for an alkane is C(n)H(2n+2) \newline Alkanes are non-polar (only C-H bonds)}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{p{1.64241 cm} p{3.33459 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Common Functional Groups}}  \tn
% Row 0
\SetRowColor{LightBackground}
F & Flouro \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
Cl & Chloro \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
Br & bromo \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
I & iodo \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
NO2 & nitro \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
NH2 & amino \tn 
% Row Count 6 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Alkenes}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{General formula for alkenes is C(n)H(2n)} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Alkenes contain a carbon to carbon double bond} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Non-polar} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Suffix if highest precedence is -ene} \tn 
% Row Count 4 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Alkynes}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Alkynes have carbon-carbon triple bonds} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{General formula for alkynes is C(n)H(2n-2)} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Non polar} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{suffix is -yne if highest precedence} \tn 
% Row Count 4 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Cyclic Aliphatics}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Cyclic compounds occur when carbon atoms are arranged to form rings} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{General formula for cyclic compounds are: C2H2n (cycloalkane), C2H2n-2 (cycloalkene), C2H2n-4 (cycloalkane).} \tn 
% Row Count 5 (+ 3)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Non-Polar} \tn 
% Row Count 6 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Prefix is cyclo} \tn 
% Row Count 7 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{2.04057 cm} x{2.93643 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Aromatic nomenclature}}  \tn
% Row 0
\SetRowColor{LightBackground}
F & Flourobenzene \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
Br & Bromobenzene \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
Cl & Chlorobenzene \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
NO2 & Nitrobenzene \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
COOH & Benzoic acid \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
OH & Phenol/hydroxy benzene \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
NH2 & aniline/aminobenzene \tn 
% Row Count 7 (+ 1)
% Row 7
\SetRowColor{white}
CH3 & Toluene/methylbenzene \tn 
% Row Count 8 (+ 1)
% Row 8
\SetRowColor{LightBackground}
if 1,2 position & Ortho (o-) \tn 
% Row Count 9 (+ 1)
% Row 9
\SetRowColor{white}
if 1,3 position & Meta (m-) \tn 
% Row Count 10 (+ 1)
% Row 10
\SetRowColor{LightBackground}
if 1,4 position & Para (p-) \tn 
% Row Count 11 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{Aromatics hydrocarbons are benzene or compounds containing a benzene ring. \newline Benzene has the chemical formula C6H6}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Geometric Isomer/Structural Isomer}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Structural Isomers are when compounds have the same chemical formula,\{\{popup="https://cdn.kastatic.org/ka-perseus-images/7fa08544db1e27403fe4a2f84767cdd5c4f7d5b7.png"\}\} but a different arrangement of atoms. \newline % Row Count 5 (+ 5)
\{\{/popup\}\} \newline % Row Count 6 (+ 1)
Geometric Isomers are isomers where atoms are arranged the same but have a different 3-d arrangement. Alkenes can form cis-trans isomers \{\{popup="https://useruploads.socratic.org/ljyupDzsSyingXxGfQyz\_butene\_5.png"\}\}Alkenes can form cis-trans isomers.\{\{/popup\}\}% Row Count 12 (+ 6)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{1.44333 cm} x{3.53367 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Intermolecular Forces}}  \tn
% Row 0
\SetRowColor{LightBackground}
LDF & Very weak forces that exist in all atoms/molecules caused by {\bf{instantaneous dipoles}}, become stronger as molecule gets larger \tn 
% Row Count 5 (+ 5)
% Row 1
\SetRowColor{white}
\seqsplit{Dipole-Dipole} & Strong attraction force between opposite charges of polar molecules \tn 
% Row Count 8 (+ 3)
% Row 2
\SetRowColor{LightBackground}
Hydrogen bonding & Very strong dipole-dipole forces with H atoms covalently bonded with an N, O or F atom \tn 
% Row Count 12 (+ 4)
% Row 3
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{} \tn 
% Row Count 12 (+ 0)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{(strength is in descending order)}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Emprical and Molecular Formulas}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{n = m/MM} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{m = m x MM} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{E.F = simplest formula} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{M.F = MM actual/MM empirical formula} \tn 
% Row Count 4 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{1.14425 cm} x{1.73926 cm} x{1.69349 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{3}{x{5.377cm}}{\bf\textcolor{white}{Functional Groups in descending order}}  \tn
% Row 0
\SetRowColor{LightBackground}
\seqsplit{Functional} Group & Prefix & Suffix \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\seqsplit{Carboxylic} Acid &  & -oic acid \tn 
% Row Count 4 (+ 2)
% Row 2
\SetRowColor{LightBackground}
Ester &  & {[}branch{]}-yl {[}root{]}-oate \tn 
% Row Count 6 (+ 2)
% Row 3
\SetRowColor{white}
Amide &  & -amide \tn 
% Row Count 7 (+ 1)
% Row 4
\SetRowColor{LightBackground}
Aldehyde & formyl / oxo & -al \tn 
% Row Count 8 (+ 1)
% Row 5
\SetRowColor{white}
Ketone & oxo & -one \tn 
% Row Count 9 (+ 1)
% Row 6
\SetRowColor{LightBackground}
Alcohol & hydroxy & -ol \tn 
% Row Count 10 (+ 1)
% Row 7
\SetRowColor{white}
Amine & amino & -amine \tn 
% Row Count 11 (+ 1)
% Row 8
\SetRowColor{LightBackground}
\seqsplit{Alkene/Alkyne} &  & -ene/-yne \tn 
% Row Count 13 (+ 2)
% Row 9
\SetRowColor{white}
\mymulticolumn{3}{x{5.377cm}}{Alkane} \tn 
% Row Count 14 (+ 1)
% Row 10
\SetRowColor{LightBackground}
Ether & -oxy &  \tn 
% Row Count 15 (+ 1)
% Row 11
\SetRowColor{white}
Alkyl Halide & \seqsplit{flouro/chloro/bromo/iodo} &  \tn 
% Row Count 17 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}---}
\SetRowColor{LightBackground}
\mymulticolumn{3}{x{5.377cm}}{Note: for Alkene/Alkynes, to determine which takes higher priority, choose for which ever gives the better number combination for side groups, if same then go alphabetically (ene \textgreater{} yne)}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}---}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{1.08602 cm} p{0.45947 cm} p{0.75186 cm} x{1.87965 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{4}{x{5.377cm}}{\bf\textcolor{white}{Functional Groups characteristics}}  \tn
% Row 0
\SetRowColor{LightBackground}
\seqsplit{Functional} Group & \seqsplit{Polarity} & \seqsplit{Solubility} & B.P/M.P \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
Alkane & \seqsplit{Non-Polar} & \seqsplit{Slightly} \seqsplit{Soluble} & Depends on Length, more C = Higher, less C = Lower \tn 
% Row Count 5 (+ 3)
% Row 2
\SetRowColor{LightBackground}
Alkene & Non- Polar & \seqsplit{Slightly} \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 8 (+ 3)
% Row 3
\SetRowColor{white}
Alkyne & \seqsplit{Non-Polar} & \seqsplit{Slightly} \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 11 (+ 3)
% Row 4
\SetRowColor{LightBackground}
\seqsplit{Cycloalkyl} & \seqsplit{Non-Polar} & \seqsplit{Slightly} \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 14 (+ 3)
% Row 5
\SetRowColor{white}
Alcohol & Polar & Very \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 16 (+ 2)
% Row 6
\SetRowColor{LightBackground}
\seqsplit{Aldehydes/Ketone} & Polar & Very \seqsplit{Soluble} & Very High \tn 
% Row Count 18 (+ 2)
% Row 7
\SetRowColor{white}
\seqsplit{Carboxylic} \seqsplit{Acids/Esters} & Polar & Very \seqsplit{Soluble} & Very High \tn 
% Row Count 21 (+ 3)
% Row 8
\SetRowColor{LightBackground}
Ethers & Polar & Very \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 23 (+ 2)
% Row 9
\SetRowColor{white}
\seqsplit{Amines/Amides} & Polar & Very \seqsplit{Soluble} & Depends on Length of parent C chain \tn 
% Row Count 25 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}----}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{2.09034 cm} x{2.88666 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Organic Reactions I}}  \tn
% Row 0
\SetRowColor{LightBackground}
\seqsplit{Combustion/Complete} Oxidation & Adding Oxygen or Removing Hydrogen \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
Substitution & Replacing a hydrogen for a Halogen (Halogenation) \tn 
% Row Count 5 (+ 3)
% Row 2
\SetRowColor{LightBackground}
Addition of Alkanes & Breaking double bond by adding Halogen (Halogenation) , Hydrogen (Hydrogenation), or Water (Hydration) \tn 
% Row Count 10 (+ 5)
% Row 3
\SetRowColor{white}
Elimination of Alkanes & The opposite of Addition \tn 
% Row Count 12 (+ 2)
% Row 4
\SetRowColor{LightBackground}
Mild Oxidation Reactions & Using Oxidizing agents to turn Primary alcohols into aldehydes/carboxylic acids, and secondary alcohols into ketones. \tn 
% Row Count 18 (+ 6)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{Remember Markovniks Rule: "Rich get richer" \newline Tertiary alcohols do not react in mild oxidation reactions}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{1.89126 cm} x{3.08574 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Benzene Reactions}}  \tn
% Row 0
\SetRowColor{LightBackground}
Halogenation & Benzene + Halogen \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
Nitration (Dehydration) & Benzene + HNO3 (in acidic conditions) \tn 
% Row Count 3 (+ 2)
% Row 2
\SetRowColor{LightBackground}
Alkylation & Benzene + Alkylhalide \tn 
% Row Count 4 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{2.4885 cm} x{2.4885 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Organic Reactions II  Reactions}}  \tn
% Row 0
\SetRowColor{LightBackground}
Formation of Ethers \seqsplit{(Condensation/Dehydration)} & Alcohol + Alcohol -{}-\textgreater{} Ether \tn 
% Row Count 3 (+ 3)
% Row 1
\SetRowColor{white}
Formation of Esters \seqsplit{(Condensation/Dehydration)} & Alcohol + Carboxylic Acid -{}-\textgreater{} ester \tn 
% Row Count 6 (+ 3)
% Row 2
\SetRowColor{LightBackground}
Decomposition of Esters (Hydrolosis) & Ester -{}-\textgreater{} Alcohol + Carboxylic Acid \tn 
% Row Count 8 (+ 2)
% Row 3
\SetRowColor{white}
Formation of Amides \seqsplit{(Condensation/Dehydration)} & Amine + Carboxylic Acid -{}-\textgreater{} Amide + H2O \tn 
% Row Count 11 (+ 3)
% Row 4
\SetRowColor{LightBackground}
Decomposition of Amides (Hydrolosis) & Amide + H2O -{}-{}-\textgreater{} Amine + Carboxylic Acid \tn 
% Row Count 13 (+ 2)
% Row 5
\SetRowColor{white}
Synthesis of Primary Amines (Substitution) & Alkyl Halide + ammonia -{}-{}-\textgreater{} Primary Amine \tn 
% Row Count 16 (+ 3)
% Row 6
\SetRowColor{LightBackground}
Synthesis of Secondary Amines (Substitution) & Alkyl Halide + Primary Amine -{}-{}-\textgreater{} Secondary Amine \tn 
% Row Count 19 (+ 3)
% Row 7
\SetRowColor{white}
Synthesis of Tertiary Amines (Substitution) & Alkyl Halide + Secondary Amine -{}-{}-\textgreater{} Tertiary Amine \tn 
% Row Count 22 (+ 3)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{Polymers}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Large Molecule that are composed of many repeated subunits are called monomers} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Created through polymerization} \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Polymerization (addition - chain reaction of alkene) CxHy + CxHy+ CxHy+ ...  -{}-\textgreater{} {[}CxHy{]}n} \tn 
% Row Count 5 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Polymerization (condensation with alcohol - polyester) HOCxHyOH + HOOCCxHyCOOH + ... -{}-{}-\textgreater{} {[}O2CCxHyO2CxHyO2{]}n} \tn 
% Row Count 8 (+ 3)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Polymerization (condensation with alcohol - polyamide) H2NCxHyNH2 + HOOCCxHyCOOH + ... -{}-\textgreater{} {[}NOCCxHyO2CxHyON{]}n} \tn 
% Row Count 11 (+ 3)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Polymerization (condensation) need the \newline reacting functional groups to be on both \newline sides of the monomers to be able to \newline complete the chain reaction (-dioic acid, - \newline diol, -diamine)}  \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}