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% Most of the following are not required for the majority
% of cheat sheets but are needed for some symbol support.
\usepackage{amsmath}            % Symbols
\usepackage{MnSymbol}           % Symbols
\usepackage{wasysym}            % Symbols
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% Document Info
\author{CS\_lnbr}
\pdfinfo{
  /Title (matlab.pdf)
  /Creator (Cheatography)
  /Author (CS\_lnbr)
  /Subject (MATLAB Cheat Sheet)
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\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{C}
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    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{MATLAB Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{CS\_lnbr} via \textcolor{DarkBackground}{\uline{cheatography.com/145554/cs/31366/}}}
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\noindent
\begin{multicols}{3}
\begin{tabulary}{5.8cm}{LL}
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}CS\_lnbr \\
  \uline{cheatography.com/cs-lnbr} \\
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 28th April, 2022.\\
   Page {\thepage} of \pageref{LastPage}.
\end{tabulary}
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  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
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\begin{document}
\raggedright
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% Set font size to small. Switch to any value
% from this page to resize cheat sheet text:
% www.emerson.emory.edu/services/latex/latex_169.html
\footnotesize % Small font.

\begin{multicols*}{4}

\begin{tabularx}{3.833cm}{p{0.58361 cm} x{2.84939 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{3.833cm}}{\bf\textcolor{white}{Calculations}}  \tn
% Row 0
\SetRowColor{LightBackground}
+, - & addition/subtraction (elementwise) \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
*,/ & multiplication/division \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
a\textasciicircum{}b & power of a \tn 
% Row Count 4 (+ 1)
% Row 3
\SetRowColor{white}
\seqsplit{sqrt(a)} & square root of a \tn 
% Row Count 6 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{x{1.20155 cm} x{2.23145 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{3.833cm}}{\bf\textcolor{white}{Variables}}  \tn
% Row 0
\SetRowColor{LightBackground}
a = 1 & Define variable a to be 5. If you apply another value to this variable, it will be overwritten! \tn 
% Row Count 4 (+ 4)
% Row 1
\SetRowColor{white}
b = 2; & ; suppresses output \tn 
% Row Count 5 (+ 1)
% Row 2
\SetRowColor{LightBackground}
e = sym('e') or syms e & Define symbolic variable e \tn 
% Row Count 7 (+ 2)
% Row 3
\SetRowColor{white}
syms a b c d & Define several symbolic variables \tn 
% Row Count 9 (+ 2)
% Row 4
\SetRowColor{LightBackground}
h = 2*e + f\textasciicircum{}2 & Calculations with symbolic variables \tn 
% Row Count 11 (+ 2)
% Row 5
\SetRowColor{white}
mod(a,b) & remainder after division \tn 
% Row Count 12 (+ 1)
% Row 6
\SetRowColor{LightBackground}
z = 3 +4i & Define complex variable \tn 
% Row Count 13 (+ 1)
% Row 7
\SetRowColor{white}
real(z) & real part of complex number \tn 
% Row Count 15 (+ 2)
% Row 8
\SetRowColor{LightBackground}
imag(z) & imaginary part of complex number \tn 
% Row Count 17 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{x{0.92691 cm} x{2.50609 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{3.833cm}}{\bf\textcolor{white}{Matrix operations}}  \tn
% Row 0
\SetRowColor{LightBackground}
zeros(n) & Creates a n x n matrix of zeros \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
zeros(m,n) & Creates a m x n matrix of zeros \tn 
% Row Count 4 (+ 2)
% Row 2
\SetRowColor{LightBackground}
ones(n) & Creates a n x n matrix of ones \tn 
% Row Count 6 (+ 2)
% Row 3
\SetRowColor{white}
ones(m,n) & Creates a m x n matrix of ones \tn 
% Row Count 8 (+ 2)
% Row 4
\SetRowColor{LightBackground}
eye(n) & Creates a n x n identity matrix \tn 
% Row Count 10 (+ 2)
% Row 5
\SetRowColor{white}
rand(m,n) & Creates a m x n matrix of random numbers \tn 
% Row Count 12 (+ 2)
% Row 6
\SetRowColor{LightBackground}
diag({[}a,b,c,d{]}) & Creates a diagonal matrix with a, b, c, d \tn 
% Row Count 14 (+ 2)
% Row 7
\SetRowColor{white}
A = {[}1 2; 3 4{]} & Creates a matrix with specified numbers - rows separated by whitespace, columns by semicolon \tn 
% Row Count 18 (+ 4)
% Row 8
\SetRowColor{LightBackground}
AA = {[}1,2;3,4{]} & Creates a matrix with specified numbers - rows separated by comma, columns by semicolon \tn 
% Row Count 21 (+ 3)
% Row 9
\SetRowColor{white}
size(A) & Returns dimensions of matrix A \tn 
% Row Count 23 (+ 2)
% Row 10
\SetRowColor{LightBackground}
v = {[}5;6{]} & Vectors are created as single-line matrices. Column vector \tn 
% Row Count 25 (+ 2)
% Row 11
\SetRowColor{white}
u = {[}5,6{]} & Vectors are created as single-line matrices. Row vector \tn 
% Row Count 27 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
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\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{3.833cm}}{\bf\textcolor{white}{L{\"o}sen von Gleichungen}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{3.833cm}}{Numerisches L{\"o}sen von linearen Gleichungssystemen: \newline % Row Count 2 (+ 2)
{\bf{linsolve}} \newline % Row Count 3 (+ 1)
Symbolisches L{\"o}sen von nicht-linearen Gleichungen oder Gleichungssystemen: \newline % Row Count 5 (+ 2)
{\bf{solve(rechte Seite == linke Seite, Variable)}} \newline % Row Count 6 (+ 1)
Mehrere Gleichungen und Unbekannte werden als {\bf{Zeilenvektor}} eingegeben: \newline % Row Count 8 (+ 2)
Bsp: loesung = solve({[}x1-2*x2 == x3, x2\textasciicircum{}2 == -1, x3-x2 == 2{]}, {[}x1,x2,x3{]}) \newline % Row Count 10 (+ 2)
Ausgabe ist eine {\bf{structure}}. Zugriff auf die einzelnen Elemente über: \newline % Row Count 12 (+ 2)
loesung.x1 \newline % Row Count 13 (+ 1)
loesung.x2 \newline % Row Count 14 (+ 1)
Ist eine symbolische L{\"o}sung nicht m{\"o}glich, liefert solve eine {\bf{numerische N{\"a}herung}} (mit einer Warnung). \newline % Row Count 17 (+ 3)
Finden von numerischen N{\"a}herungen: \newline % Row Count 18 (+ 1)
{\bf{fzero(Funktion, x0)}} \newline % Row Count 19 (+ 1)
x0 kann ein Skalar oder ein Vektor der L{\"a}nge 2 (= Intervall)) sein.% Row Count 21 (+ 2)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{3.833cm}}{\bf\textcolor{white}{L{\"o}sen von gew{\"o}hnlichen Differentialgleichungen}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{3.833cm}}{Differentialgleichung der Form {\bf{f(yn,yn-1, ..., y'', y', y) = g(x)}} \newline % Row Count 2 (+ 2)
{\bf{dsolve(Gleichung, Anfangsbedingungen)}} \newline % Row Count 3 (+ 1)
{\bf{Bsp:}} \newline % Row Count 4 (+ 1)
syms Q(t) \newline % Row Count 5 (+ 1)
dQ = diff(Q,1) \% Ableitung von Q \newline % Row Count 6 (+ 1)
eqn = 1/(R{\emph{C)}}Q + dQ == U/R \% Differentialgleichung \newline % Row Count 8 (+ 2)
sol = dsolve(eqn, Q(0) == 0) \newline % Row Count 9 (+ 1)
Die L{\"o}sung zeichnen: \newline % Row Count 10 (+ 1)
figure; \newline % Row Count 11 (+ 1)
fplot(sol, {[}0,50{]}) \newline % Row Count 12 (+ 1)
Man kann Anfangswertprobleme auch numerisch l{\"o}sen, wofür verschiedene Probleme zur Verfügung stehen.% Row Count 15 (+ 3)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
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\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{3.833cm}}{\bf\textcolor{white}{Iterationen und Schleifen, If-Else-Statements}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{3.833cm}}{If-Else-Anweisung: \newline % Row Count 1 (+ 1)
**if condition \newline % Row Count 2 (+ 1)
      dann \newline % Row Count 3 (+ 1)
elseif condition \newline % Row Count 4 (+ 1)
      dann \newline % Row Count 5 (+ 1)
else \newline % Row Count 6 (+ 1)
      dann \newline % Row Count 7 (+ 1)
end** \newline % Row Count 8 (+ 1)
For-Anweisung: \newline % Row Count 9 (+ 1)
**for index = werte: \newline % Row Count 10 (+ 1)
    statement \newline % Row Count 11 (+ 1)
end** \newline % Row Count 12 (+ 1)
While-Schleife \newline % Row Count 13 (+ 1)
k = 0 \newline % Row Count 14 (+ 1)
while condition \newline % Row Count 15 (+ 1)
   statement \newline % Row Count 16 (+ 1)
end% Row Count 17 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{3.833cm}}{\bf\textcolor{white}{Differenzieren}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{3.833cm}}{Bildung der Ableitung eines Ausdrucks: \newline % Row Count 1 (+ 1)
{\bf{diff(Ausdruck, Ableitung nach, n. Ableitung)}} \newline % Row Count 2 (+ 1)
Partielle Ableitung: \newline % Row Count 3 (+ 1)
{\bf{diff(Ausdruck, Ableitung nach x, Ableitung nach y)}} \newline % Row Count 5 (+ 2)
- Ergebnis wird nicht sofort vereinfacht (-\textgreater{} simplify) \newline % Row Count 7 (+ 2)
- Ergebnis ist keine Funktion \newline % Row Count 8 (+ 1)
Bildung einer Funktion mittels Substitution: \newline % Row Count 9 (+ 1)
{\bf{subs(Ausdruck, \{alte Variablen\}, \{neue Variablen\})}} \newline % Row Count 11 (+ 2)
Bsp: h = @(xx,yy) subs(g, \{x,y\}, \{xx,yy\})** \newline % Row Count 12 (+ 1)
{\bf{Ableitung für numerische Objekte}} \newline % Row Count 13 (+ 1)
- {\bf{Input:}} Ausdruck, Vektor mit Funktionswerten \newline % Row Count 14 (+ 1)
- {\bf{Output:}} Vektor mit Werten der Ableitung \newline % Row Count 15 (+ 1)
- diff() liefert bei num. Argumenten nur eine N{\"a}herung der symbolischen Ableitung \newline % Row Count 17 (+ 2)
- Wegen Bildung der Differenzen hat das Ergebnis eine Komponente weniger% Row Count 19 (+ 2)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{3.833cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{3.833cm}}{\bf\textcolor{white}{Integration}}  \tn
\SetRowColor{white}
\mymulticolumn{1}{x{3.833cm}}{Für viele Funktionen kennt Matlab die zugeh{\"o}rige Stammfunktion: \newline % Row Count 2 (+ 2)
Unbestimmtes Integral: {\bf{int(f,x)}} \newline % Row Count 3 (+ 1)
Bestimmtes Integral: {\bf{int(f,x,a,b)}}  \newline % Row Count 4 (+ 1)
Das bestimmte Integral muss durch {\bf{eval(ergebnis)}} noch ausgewertet werden. \newline % Row Count 6 (+ 2)
Es sind mehrere Variablen m{\"o}glich, wenn man die Integrale verschachtelt: \newline % Row Count 8 (+ 2)
{\bf{int(int(s*y,x),y)}} \newline % Row Count 9 (+ 1)
int() kann keine numerischen Elemente auswerten. Es gibt jedoch Befehle, die Vergleichbares liefern: \newline % Row Count 12 (+ 3)
{\bf{trapz}} berechnet die Fl{\"a}che unter einer Kurve nach der Simpson'schen Trapezregel (Output: Zahl) \newline % Row Count 14 (+ 2)
{\bf{cumsum}} berechnet die kumulative Summe der Vektorelemente. Ergebnis ist wieder ein Vektor, der der Stammfunktion entspricht und ggf. noch um die Integrationskonstante verschoben werden muss. \newline % Row Count 18 (+ 4)
Numerische Integration (= numerisches Berechnen eines symbolisch gegebenen Integrals) \newline % Row Count 20 (+ 2)
{\bf{integral(Ausdruck, a, b) }} \newline % Row Count 21 (+ 1)
{\bf{integral2(Ausdruck, xmin, xmax, ymin, ymax)}} (2-fach Integral) \newline % Row Count 23 (+ 2)
{\bf{integral3}} (3-fach Integral)% Row Count 24 (+ 1)
} \tn 
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}