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\author{Jaco (brandenz1229)}
\pdfinfo{
  /Title (physics-final-cheat-sheet.pdf)
  /Creator (Cheatography)
  /Author (Jaco (brandenz1229))
  /Subject (Physics Final Cheat Sheet)
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        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Physics Final Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{Jaco (brandenz1229)} via \textcolor{DarkBackground}{\uline{cheatography.com/138824/cs/30208/}}}
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}Jaco (brandenz1229) \\
  \uline{cheatography.com/brandenz1229} \\
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Published 15th December, 2021.\\
   Updated 15th December, 2021.\\
   Page {\thepage} of \pageref{LastPage}.
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  Measure your website readability!\\
  www.readability-score.com
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\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{x{2.4885 cm} x{2.4885 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 2: Motion along A Straight Line}}  \tn
% Row 0
\SetRowColor{LightBackground}
s = speed & t = time \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
Total Distance & x`f`+x`i` \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{One Dimensional Motion}}} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
Distance & d = s⋅t \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
Displacement & x`f`-x`i` \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
Speed & (x`f`+x`i`) / (t`f`+`t`i`) \tn 
% Row Count 7 (+ 2)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Not Constant Velocity}}} \tn 
% Row Count 8 (+ 1)
% Row 7
\SetRowColor{white}
Average Velocity & (x`f`-x`i`) / (t`f`-`t`i`) \tn 
% Row Count 10 (+ 2)
% Row 8
\SetRowColor{LightBackground}
x↑: v+ \{\{nl\}\} x↓: v- \{\{nl\}\} x→: v=0 & a+: v↑ \{\{nl\}\} a-: v↓ \{\{nl\}\} a=0: v→ \tn 
% Row Count 13 (+ 3)
% Row 9
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Instantaneous Acceleration}}} \tn 
% Row Count 14 (+ 1)
% Row 10
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{(v`f`-v`i`) / (t`f`-`t`i`)} \tn 
% Row Count 15 (+ 1)
% Row 11
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Constant Acceleration in 1D}}} \tn 
% Row Count 16 (+ 1)
% Row 12
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{V`f` = V`i` + (a⋅t)} \tn 
% Row Count 17 (+ 1)
% Row 13
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Constant Acceleration Final Distance}}} \tn 
% Row Count 18 (+ 1)
% Row 14
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{X`f`= 1/2(V`f`-V`i`) ⋅ t} \tn 
% Row Count 19 (+ 1)
% Row 15
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{X`f`= X`i` + (V`i`⋅ t) + 1/2(a ⋅ t)} \tn 
% Row Count 20 (+ 1)
% Row 16
\SetRowColor{LightBackground}
a = (V`f`-V`i`) / t & t = (V`f`-V`i`) / a \tn 
% Row Count 21 (+ 1)
% Row 17
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{V`f` = V`i`⋅ a\textasciicircum{}2\textasciicircum{}} \tn 
% Row Count 22 (+ 1)
% Row 18
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{V`f`\textasciicircum{}2\textasciicircum{} = V`i`\textasciicircum{}2\textasciicircum{} +  2⋅a (x`f`-x`i`)} \tn 
% Row Count 23 (+ 1)
% Row 19
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{G`y` = -9.8 m/s} \tn 
% Row Count 24 (+ 1)
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\begin{tabularx}{5.377cm}{x{2.93643 cm} x{2.04057 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 14: Periodic Motion}}  \tn
% Row 0
\SetRowColor{LightBackground}
{\bf{Angular Frequency}} & w = 2πf \{\{nl\}\} 2π/T \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
{\bf{Frequency}} & f = 1 / T \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
{\bf{Period}} & T = 1 / f \tn 
% Row Count 4 (+ 1)
% Row 3
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{\bf{Restoring Force}} & F`x` = -kx \tn 
% Row Count 5 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Simple Harmonic Motion}}} \tn 
% Row Count 6 (+ 1)
% Row 5
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k = Spring Constant & x = displacement \tn 
% Row Count 7 (+ 1)
% Row 6
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\mymulticolumn{2}{x{5.377cm}}{m = mass} \tn 
% Row Count 8 (+ 1)
% Row 7
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{\bf{Displacement as function of time}} & x = Acos(wt + Θ) \tn 
% Row Count 10 (+ 2)
% Row 8
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{\bf{Velocity as function of time}} & v = -wAsin(wt + Θ) \tn 
% Row Count 12 (+ 2)
% Row 9
\SetRowColor{white}
{\bf{Acceleration as function of time}} & a = -w\textasciicircum{}2\textasciicircum{}Acos(wt + Θ) \tn 
% Row Count 14 (+ 2)
% Row 10
\SetRowColor{LightBackground}
{\bf{x`max`}} = A {[}Amplitude{]} & {\bf{-x`max`}} = A {[}Amplitude{]} \tn 
% Row Count 16 (+ 2)
% Row 11
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{\bf{v`max`}} = wA & {\bf{-v`max`}} = wA \tn 
% Row Count 17 (+ 1)
% Row 12
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{\bf{a`max`}} = w\textasciicircum{}2\textasciicircum{}A & {\bf{-a`max`}} = w\textasciicircum{}2\textasciicircum{}A \tn 
% Row Count 19 (+ 2)
% Row 13
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{\bf{Equation for Simple Harmonic Motion}} & a`x = - (k/m) x \tn 
% Row Count 21 (+ 2)
% Row 14
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\mymulticolumn{2}{x{5.377cm}}{k = restoring force} \tn 
% Row Count 22 (+ 1)
% Row 15
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{\bf{Angular Frequency for SHM}} & w = √k/m \tn 
% Row Count 24 (+ 2)
% Row 16
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{\bf{Frequency for SHM}} & f = w/2π \tn 
% Row Count 25 (+ 1)
% Row 17
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 & f = 1/2π√k/m \tn 
% Row Count 26 (+ 1)
% Row 18
\SetRowColor{LightBackground}
{\bf{Period for SHM}} & T = 1/f \tn 
% Row Count 27 (+ 1)
% Row 19
\SetRowColor{white}
 & T = 2π/w \tn 
% Row Count 28 (+ 1)
% Row 20
\SetRowColor{LightBackground}
 & T = 2π√m/k \tn 
% Row Count 29 (+ 1)
% Row 21
\SetRowColor{white}
{\bf{Total Mechanical Energy}} (Constant) & E = 1/2mv`x`\textasciicircum{}2\textasciicircum{} + 1/2kx\textasciicircum{}2\textasciicircum{} \tn 
% Row Count 31 (+ 2)
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\begin{tabularx}{5.377cm}{x{2.93643 cm} x{2.04057 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 14: Periodic Motion (cont)}}  \tn
% Row 22
\SetRowColor{LightBackground}
 & E =  1/2kA\textasciicircum{}2\textasciicircum{} \tn 
% Row Count 1 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
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\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 6: Work and Kinetic Energy}}  \tn
% Row 0
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1km = 1000m & 1 kg = 1000g \tn 
% Row Count 1 (+ 1)
% Row 1
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{\bf{Dot Product}} & P = Power \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
A⋅B = \seqsplit{(A`i`⋅B`i`)+(A`j`⋅B`j`)} & t = s \tn 
% Row Count 4 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{Work = Force ⋅ distance} \tn 
% Row Count 5 (+ 1)
% Row 4
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\mymulticolumn{2}{x{5.377cm}}{W = F`x`⋅ distance} \tn 
% Row Count 6 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{W = F⋅cosΘ⋅distance} \tn 
% Row Count 7 (+ 1)
% Row 6
\SetRowColor{LightBackground}
K`E`: 1/2⋅m⋅v\textasciicircum{}2\textasciicircum{} & U = m⋅g⋅h \tn 
% Row Count 8 (+ 1)
% Row 7
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{W`total` = K`E``f` - K`E``i`} \tn 
% Row Count 9 (+ 1)
% Row 8
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{W`x` = F (cosΘ)⋅s    ||    W`y` = F (sinΘ)⋅s} \tn 
% Row Count 10 (+ 1)
% Row 9
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Constant Speed}}} \tn 
% Row Count 11 (+ 1)
% Row 10
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{Friction (opposite) = cos(180\textasciicircum{}o\textasciicircum{})} \tn 
% Row Count 12 (+ 1)
% Row 11
\SetRowColor{white}
P = F⋅v & P = (W/t) \tn 
% Row Count 13 (+ 1)
% Row 12
\SetRowColor{LightBackground}
P`av`= ΔW / Δt {[}Average Power{]} & if F→ \& s← = - W \tn 
% Row Count 15 (+ 2)
% Row 13
\SetRowColor{white}
if F↓ \& s→ = 0 & if F→ \& s→ =  W \tn 
% Row Count 17 (+ 2)
% Row 14
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Force Required to \{\{nl\}\}  Stretch a spring}}} \tn 
% Row Count 18 (+ 1)
% Row 15
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{F`x` = k ⋅ x} \tn 
% Row Count 19 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
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\begin{tabularx}{5.377cm}{x{2.4885 cm} x{2.4885 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 13: Newton's Law of Gravitation}}  \tn
% Row 0
\SetRowColor{LightBackground}
G`E`= 6.67⋅10\textasciicircum{}-11\textasciicircum{} & Earth Gravity Constant \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
R`E`= 6.38⋅10\textasciicircum{}6\textasciicircum{} m & Earth Radius \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
M`E`= 5.972⋅10\textasciicircum{}24\textasciicircum{} kg & Mass of Earth \tn 
% Row Count 5 (+ 2)
% Row 3
\SetRowColor{white}
g = 9.8 m/s; a`g` = 9.8 m/s & r - R`E` = h \tn 
% Row Count 7 (+ 2)
% Row 4
\SetRowColor{LightBackground}
F`g` = \seqsplit{(G`E`⋅m`1`⋅m`2`)} / (r\textasciicircum{}2\textasciicircum{}) & F`g` = m ⋅ a \tn 
% Row Count 9 (+ 2)
% Row 5
\SetRowColor{white}
w = m⋅g & s = r - R`E` cosΘ \tn 
% Row Count 10 (+ 1)
% Row 6
\SetRowColor{LightBackground}
{\bf{Gravitation and Spherically \{\{nl\}\} Symmetric Bodies}} & F`g` = (G`E`⋅m`E`⋅m) / (r\textasciicircum{}2\textasciicircum{}) \tn 
% Row Count 13 (+ 3)
% Row 7
\SetRowColor{white}
{\bf{Weight of the body at Earth's Surface}} & w = F`g` = (G`E`⋅m`E`⋅m) / (R`E`\textasciicircum{}2\textasciicircum{}) \tn 
% Row Count 16 (+ 3)
% Row 8
\SetRowColor{LightBackground}
{\bf{Acceleration due to Gravity}} & g = (G`E`⋅m`E`) / (R`E`\textasciicircum{}2\textasciicircum{}) \tn 
% Row Count 18 (+ 2)
% Row 9
\SetRowColor{white}
{\bf{Velocity of Earth}} & V`E`= 4/3πR`E`\textasciicircum{}2\textasciicircum{} = 1.08⋅10\textasciicircum{}21\textasciicircum{} m\textasciicircum{}3\textasciicircum{} \tn 
% Row Count 20 (+ 2)
% Row 10
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Gravitational Potential Energy}}} \tn 
% Row Count 21 (+ 1)
% Row 11
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{U = -(G`E`⋅m`E`⋅m) / (r)} \tn 
% Row Count 22 (+ 1)
% Row 12
\SetRowColor{LightBackground}
{\bf{WorkDone by Gravity}} & W`grav` = m⋅g(r`1`-r`2`) \tn 
% Row Count 24 (+ 2)
% Row 13
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{W`grav` = Gm`E`⋅m ⋅  (r`1`-r`2`) / (r`1`⋅r`2`)} \tn 
% Row Count 26 (+ 2)
% Row 14
\SetRowColor{LightBackground}
W`grav`= Gm`E`⋅m ⋅  (r`1`-r`2`) / (R`E`\textasciicircum{}2\textasciicircum{}) & {[}if the body stays close to Earth{]} \tn 
% Row Count 29 (+ 3)
% Row 15
\SetRowColor{white}
{\bf{Speed of the Satellite}} & v = √(G⋅m`E` / r) \tn 
% Row Count 31 (+ 2)
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\vfill
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\begin{tabularx}{5.377cm}{x{2.4885 cm} x{2.4885 cm} }
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\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 13: Newton's Law of Gravitation (cont)}}  \tn
% Row 16
\SetRowColor{LightBackground}
{\bf{Period of Circular Orbit}} & T = (2πr / v) \tn 
% Row Count 2 (+ 2)
% Row 17
\SetRowColor{white}
T = 2πr\textasciicircum{}3/2\textasciicircum{}/√G⋅m`E` & T = 2πr √(r / G⋅m`E`) \tn 
% Row Count 4 (+ 2)
% Row 18
\SetRowColor{LightBackground}
{\bf{Point Mass Outside \{\{nl\}\} a Spherical Shell}} & U`i`= - Gm⋅m`i` / s \tn 
% Row Count 7 (+ 3)
% Row 19
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Apparent weight \{\{nl\}\} ; Earth's Rotation}}} \tn 
% Row Count 8 (+ 1)
% Row 20
\SetRowColor{LightBackground}
w`0` = true weight of object & F = force exerted by spring scale \tn 
% Row Count 10 (+ 2)
% Row 21
\SetRowColor{white}
F + w`0` = net force on object & w = apparent weight = opposite of F \tn 
% Row Count 12 (+ 2)
% Row 22
\SetRowColor{LightBackground}
{\bf{centripetal acceleration}}` & w`0`- F = (mv\textasciicircum{}2\textasciicircum{} / R`E`) \tn 
% Row Count 14 (+ 2)
% Row 23
\SetRowColor{white}
 & w = w`0` - (mv\textasciicircum{}2\textasciicircum{} / R`E`) \tn 
% Row Count 16 (+ 2)
% Row 24
\SetRowColor{LightBackground}
{\bf{freefall acceleration}} & g = g`0` - (v\textasciicircum{}2\textasciicircum{}/ R`E`) \tn 
% Row Count 18 (+ 2)
% Row 25
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Black Holes}}} \tn 
% Row Count 19 (+ 1)
% Row 26
\SetRowColor{LightBackground}
P = Density & P = M / v \tn 
% Row Count 20 (+ 1)
% Row 27
\SetRowColor{white}
v = 4/3πR\textasciicircum{}3\textasciicircum{} & c = speed of light in the vaccum \tn 
% Row Count 22 (+ 2)
% Row 28
\SetRowColor{LightBackground}
{\bf{Schwardzschild Radius}} & R`s` = 2GM / c\textasciicircum{}2\textasciicircum{} \tn 
% Row Count 24 (+ 2)
% Row 29
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{c = √2GM / R`S`} \tn 
% Row Count 25 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
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\begin{tabularx}{5.377cm}{p{0.4977 cm} p{0.4977 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 7: Potential Energy, Energy Conservation}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Y-axis}} \{\{nl\}\} E = Mechanical Energy} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{W`grav` = F ⋅ s = w(y`1`-y`2`)} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{\seqsplit{W`grav`=(m⋅g⋅y`1`)-(m⋅g⋅y`1`)}} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{W`grav`=U`grav,1` - U`grav,2`} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{W`grav` = -Δ U`grav`} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Conservation \{\{nl\}\} of Mechanical Energy}}} \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{K`f`-K`i` = U`grav,1` - U`grav,2`} \tn 
% Row Count 7 (+ 1)
% Row 7
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{K`i`+U`grav,1`=K`f`+U`grav,2`} \tn 
% Row Count 8 (+ 1)
% Row 8
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{E = K + U`grav` = constant \{\{nl\}\} (if gravity does work)} \tn 
% Row Count 10 (+ 2)
% Row 9
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{When other forces \{\{nl\}\} than Gravity do work}}} \tn 
% Row Count 11 (+ 1)
% Row 10
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{W`other` + W`grav` = K`f` - K`i`} \tn 
% Row Count 12 (+ 1)
% Row 11
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Elastic Potential Energy}}} \tn 
% Row Count 13 (+ 1)
% Row 12
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{U`el` = 1/2kx\textasciicircum{}2\textasciicircum{}} \tn 
% Row Count 14 (+ 1)
% Row 13
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Work Done a Spring}}} \tn 
% Row Count 15 (+ 1)
% Row 14
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{W = 1/2kx`2`\textasciicircum{}2\textasciicircum{} - 1/2kx`1`\textasciicircum{}2\textasciicircum{}} \tn 
% Row Count 16 (+ 1)
% Row 15
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{If Elastic does work, \{\{nl\}\} total mechanical energy \{\{nl\}\} is stored}}} \tn 
% Row Count 18 (+ 2)
% Row 16
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{K`i`+U`el,1`=K`f`+U`el,2`} \tn 
% Row Count 19 (+ 1)
% Row 17
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Situations with Both Gravitational \{\{nl\}\} and Elastic Potential Energy}}} \tn 
% Row Count 21 (+ 2)
% Row 18
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{\seqsplit{K`1`+U`1`+W`other`=K`2`+U`2`}} \tn 
% Row Count 22 (+ 1)
% Row 19
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{The work done by all forces other than \{\{nl\}\} the gravitational force or \{\{nl\}\} elastic force equals the change in \{\{nl\}\} total mechanical energy \{\{nl\}\} E = K + U of the system}}} \tn 
% Row Count 26 (+ 4)
% Row 20
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{The Law of Conservation \{\{nl\}\} of Energy}}} \tn 
% Row Count 27 (+ 1)
% Row 21
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{ΔU`int` = -W`other` \{\{nl\}\} ΔU`int` = internal energy} \tn 
% Row Count 29 (+ 2)
% Row 22
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Force and Potential Energy}}} \tn 
% Row Count 30 (+ 1)
\end{tabularx}
\par\addvspace{1.3em}

\vfill
\columnbreak
\begin{tabularx}{5.377cm}{p{0.4977 cm} p{0.4977 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 7: Potential Energy, Energy Conservation (cont)}}  \tn
% Row 23
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{F`x`(x) = - dU(x) / dx} \tn 
% Row Count 1 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{x{2.4885 cm} x{2.4885 cm} }
\SetRowColor{DarkBackground}
\mymulticolumn{2}{x{5.377cm}}{\bf\textcolor{white}{Chapter 14: Periodic Motion (cont.)}}  \tn
% Row 0
\SetRowColor{LightBackground}
{\bf{The Simple Pendelum}} (TSP) & L = pendulum length \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
{\bf{Angular Frequency TSP}} & w = √k/m \tn 
% Row Count 4 (+ 2)
% Row 2
\SetRowColor{LightBackground}
 & w = √mg / L /m \tn 
% Row Count 5 (+ 1)
% Row 3
\SetRowColor{white}
 & w = √g/L \tn 
% Row Count 6 (+ 1)
% Row 4
\SetRowColor{LightBackground}
{\bf{Frequency TSP}} & f = w/2π \tn 
% Row Count 7 (+ 1)
% Row 5
\SetRowColor{white}
 & f = 1/2π √g/L \tn 
% Row Count 8 (+ 1)
% Row 6
\SetRowColor{LightBackground}
{\bf{Period TSP}} & T = 2π/w \tn 
% Row Count 9 (+ 1)
% Row 7
\SetRowColor{white}
 & T = 1/f \tn 
% Row Count 10 (+ 1)
% Row 8
\SetRowColor{LightBackground}
 & T = 2π√L/g \tn 
% Row Count 11 (+ 1)
% Row 9
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{The Physical Pendulum}} (TPP)} \tn 
% Row Count 12 (+ 1)
% Row 10
\SetRowColor{LightBackground}
L = angular momentum & L = mvr \tn 
% Row Count 13 (+ 1)
% Row 11
\SetRowColor{white}
w = Angular Velocity & w = ΔΘ / Δt \tn 
% Row Count 14 (+ 1)
% Row 12
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{(I)nertia = L / w} \tn 
% Row Count 15 (+ 1)
% Row 13
\SetRowColor{white}
{\bf{Angular Frequency TPP}} & w = √mgd / I \tn 
% Row Count 17 (+ 2)
% Row 14
\SetRowColor{LightBackground}
{\bf{Period TPP}} & T = 2π √ I / mgd \tn 
% Row Count 18 (+ 1)
% Row 15
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Damped Oscillation}}} \tn 
% Row Count 19 (+ 1)
% Row 16
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{b = Damping Constant} \tn 
% Row Count 20 (+ 1)
% Row 17
\SetRowColor{white}
{\bf{Displace of Damped}} & x = Ae\textasciicircum{}-b(2m)t\textasciicircum{} cost (wt + Θ) \tn 
% Row Count 22 (+ 2)
% Row 18
\SetRowColor{LightBackground}
{\bf{Angular Frequency of Damped}} & w' = √ (k/m) - (b\textasciicircum{}2\textasciicircum{} / 4m\textasciicircum{}2\textasciicircum{}) \tn 
% Row Count 24 (+ 2)
% Row 19
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{{\bf{Force Oscillations and Resonance}}} \tn 
% Row Count 25 (+ 1)
% Row 20
\SetRowColor{LightBackground}
F`max` = Maximum Driving Force & k = constant restoring force \tn 
% Row Count 27 (+ 2)
% Row 21
\SetRowColor{white}
\mymulticolumn{2}{x{5.377cm}}{w`d` = Driving Angular Frequency} \tn 
% Row Count 28 (+ 1)
% Row 22
\SetRowColor{LightBackground}
\mymulticolumn{2}{x{5.377cm}}{A = F`max` / √(k-mw`d`\textasciicircum{}2\textasciicircum{})\textasciicircum{}2\textasciicircum{} + b\textasciicircum{}2\textasciicircum{}w`d`\textasciicircum{}2\textasciicircum{}} \tn 
% Row Count 29 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}--}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}