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\author{aprilreynoldsss}
\pdfinfo{
  /Title (chem-121-and-122-college-ap-chemistry.pdf)
  /Creator (Cheatography)
  /Author (aprilreynoldsss)
  /Subject (CHEM 121 and 122, college/AP chemistry Cheat Sheet)
}

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\begin{tabulary}{5.8cm}{C}
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    \vspace{-7pt}
    {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent
        \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}}
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\begin{tabulary}{11cm}{L}
    \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{CHEM 121 and 122, college/AP chemistry Cheat Sheet}}}} \\
    \normalsize{by \textcolor{DarkBackground}{aprilreynoldsss} via \textcolor{DarkBackground}{\uline{cheatography.com/165644/cs/34679/}}}
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  \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}}  \\
  \vspace{-2pt}aprilreynoldsss \\
  \uline{cheatography.com/aprilreynoldsss} \\
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  \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}}  \\
   \vspace{-2pt}Not Yet Published.\\
   Updated 21st October, 2022.\\
   Page {\thepage} of \pageref{LastPage}.
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  \vspace{-5pt}
  %\includegraphics[width=48px,height=48px]{dave.jpeg}
  Measure your website readability!\\
  www.readability-score.com
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\begin{multicols*}{3}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 1: ESSENTIALS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{density=mass/volume} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{°C= 59 ×(°F−32)} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{°F= (95×°C) + 32} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{K=°C + 273.15} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{°C= K−273.15} \tn 
% Row Count 5 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 5: THERMOCHEMISTRY}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{q =(c × m × ΔT) = (c × m × (Tfinal−Tinitial))} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔU = q+w} \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔH∘ reaction = (∑n × ΔHf(products)) −( ∑n × ΔHf(reactants))} \tn 
% Row Count 5 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 8: ADV. COVALENT BONDING}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{bond order = ((number of bonding electron) − (number of antibonding electrons)) / 2} \tn 
% Row Count 2 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 10: LIQUIDS AND SOLIDS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{h=(2Tcosθ) / (rρg)} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{P=Ae\textasciicircum{}−ΔHvap/(RT)\textasciicircum{}} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{lnP=−ΔHvap/(RT)+lnA} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ln(P2/P1)= (ΔHvap/R) (1/T1−1/T2)} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{nλ=2d sinθ} \tn 
% Row Count 5 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 11: SOLUTIONS AND COLLOIDS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{C\textasciicircum{}g\textasciicircum{}=kP\textasciicircum{}g\textasciicircum{}} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{(P\textasciicircum{}A\textasciicircum{}=(X\textasciicircum{}A\textasciicircum{}) (P\textasciicircum{}A\textasciicircum{}))} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Psolution=Xsolvent Psolvent} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔT\textasciicircum{}b\textasciicircum{} = K\textasciicircum{}b\textasciicircum{}m} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔT\textasciicircum{}f\textasciicircum{} = K\textasciicircum{}f\textasciicircum{}m} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Π = MRT} \tn 
% Row Count 6 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
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\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 17: ELECTROCHEMISTRY}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{} \tn 
% Row Count 0 (+ 0)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
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\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 14: ACID-BASE EQUILIBRIA}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Kw = {[}H3O+{]}{[}OH−{]} = 1.0  ×  10\textasciicircum{}−14\textasciicircum{} (at 25 °C)} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{pH=−log{[}H3O+{]}} \tn 
% Row Count 3 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{pOH = −log{[}OH−{]}} \tn 
% Row Count 4 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{{[}H3O+{]} = 10\textasciicircum{}−pH\textasciicircum{}} \tn 
% Row Count 5 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{{[}OH−{]} = 10\textasciicircum{}−pOH\textasciicircum{}} \tn 
% Row Count 6 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{pH + pOH = pKw = 14.00 at 25 °C} \tn 
% Row Count 7 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Ka={[}H3O\textasciicircum{}+\textasciicircum{}{]}{[}A\textasciicircum{}−\textasciicircum{}{]} / {[}HA{]}} \tn 
% Row Count 8 (+ 1)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Kb={[}HB\textasciicircum{}+\textasciicircum{}{]}{[}OH\textasciicircum{}−\textasciicircum{}{]} / {[}B{]}} \tn 
% Row Count 9 (+ 1)
% Row 8
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Ka × Kb = 1.0 × 10\textasciicircum{}−14\textasciicircum{} = Kw} \tn 
% Row Count 10 (+ 1)
% Row 9
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Percent ionization = ( {[}H3O+{]}eq / {[}HA{]}0 ) ×100} \tn 
% Row Count 11 (+ 1)
% Row 10
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{pKa = −log Ka} \tn 
% Row Count 12 (+ 1)
% Row 11
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{pKb = −log Kb} \tn 
% Row Count 13 (+ 1)
% Row 12
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{pH= pKa+ log ({[}A\textasciicircum{}−\textasciicircum{}{]}/{[}HA{]})} \tn 
% Row Count 14 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 2: MOLEC, ATOMS, IONS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{average mass= ∑ i (fractional abundance × isotopic mass) i} \tn 
% Row Count 2 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 6: ELECTRONIC STRUCTURE \& PERIODIC PROP}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{c = λν} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{E = hν= hcλ ...where h= 6.626 × 10−34 J s} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{1λ = R∞(1/n\textasciicircum{}2\textasciicircum{}(\#1) −1n\textasciicircum{}2\textasciicircum{}} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{En=−kZ\textasciicircum{}2\textasciicircum{} / n\textasciicircum{}2\textasciicircum{}   ...n=1,2,3,…} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔE =kZ \textasciicircum{}2\textasciicircum{} ( 1/n \textasciicircum{}2\textasciicircum{} (\#)1 −1/n \textasciicircum{}2\textasciicircum{} (\#) 2)} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔE= kZ\textasciicircum{}2\textasciicircum{} (1/n\textasciicircum{}2\textasciicircum{}(\#1) −1/n\textasciicircum{}2\textasciicircum{}(\#2))} \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{r= ( n\textasciicircum{}2\textasciicircum{} /Z) a0} \tn 
% Row Count 7 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 9: GASSES}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{{\emph{P}} ={\emph{F/A}}} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{p = hρg} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{p = hρg} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{PvTotalv = PvAv + PvBv + PvCv + … = ƩiPi} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{PvAv = (XvAv)(PvTotalv)} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{XvAv =(nvAv)/ (n\textasciicircum{}total\textasciicircum{})} \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{rate of diffusion = (amount of gas passing through an area) / (unit of time)} \tn 
% Row Count 8 (+ 2)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{(rate of effusion of gas A / rate of effusion of gas B) = √m\textasciicircum{}B\textasciicircum{} / √m\textasciicircum{}A\textasciicircum{} =√M\textasciicircum{}B\textasciicircum{}/ √M\textasciicircum{}A\textasciicircum{}} \tn 
% Row Count 10 (+ 2)
% Row 8
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{KEavg =(3/2)(RT)} \tn 
% Row Count 11 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 12: KINETICS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{relative reaction rates for aA⟶bB =(−1/a)(Δ{[}A{]}/Δt) =(1/b)(Δ{[}B{]}/Δt)} \tn 
% Row Count 2 (+ 2)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{integrated rate law for zero-order reactions:  {[}A{]}t=−kt+{[}A{]}0} \tn 
% Row Count 4 (+ 2)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{half-life for a zero-order reaction t1/2= {[}A{]}0/(2k)} \tn 
% Row Count 6 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{integrated rate law for first-order reactions: ln{[}A{]}t=−kt + ln{[}A{]}0} \tn 
% Row Count 8 (+ 2)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{half-life for a first-order reaction t1/2= ln2/k} \tn 
% Row Count 9 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{integrated rate law for second-order reactions: 1/{[}A{]}t=kt+ 1/{[}A{]}0} \tn 
% Row Count 11 (+ 2)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{half-life for a second-order reaction t1/2 =1/({[}A{]}0k)} \tn 
% Row Count 13 (+ 2)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{k=Ae\textasciicircum{}−Ea/RT\textasciicircum{}} \tn 
% Row Count 14 (+ 1)
% Row 8
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{lnk= (−Ea/R)(1/T) + lnA} \tn 
% Row Count 15 (+ 1)
% Row 9
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{lnk(1/k2)= (Ea/R) (1/T2−1/T1)} \tn 
% Row Count 16 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 15: OTHER EQUILIBRIA}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{MpXq(s)⇌ pM\textasciicircum{}m+\textasciicircum{}(aq)+ qX\textasciicircum{}n−\textasciicircum{}(aq)} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{where    Ksp={[}M\textasciicircum{}m+\textasciicircum{}{]}\textasciicircum{}p\textasciicircum{}{[}X\textasciicircum{}n−\textasciicircum{}{]}\textasciicircum{}q\textasciicircum{}} \tn 
% Row Count 2 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 3: SUBSTANCE/SOLUTION CONCENTRATION}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{\%X=(massX / mass compound) × 100\%} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{(molecular or molar mass) / (empirical formula mass)=nformula units/molecule} \tn 
% Row Count 3 (+ 2)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{(AxBy)n = (Anx)(Bny)} \tn 
% Row Count 4 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{M=(mol solute) / (L solution)} \tn 
% Row Count 5 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{(C1)(V1) = (C2)(V2)} \tn 
% Row Count 6 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Percent by mass =(mass of solute / mass of solution) ×100} \tn 
% Row Count 8 (+ 2)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ppm = (mass solute) / (mass solution) ×10\textasciicircum{}6\textasciicircum{} ppm} \tn 
% Row Count 9 (+ 1)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ppb=(mass solute) / (mass solution) × 10\textasciicircum{}9\textasciicircum{} ppb} \tn 
% Row Count 10 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 4: STOICH/CHEM. REACTIONS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{percent yield = \{(actual yield)/(theoretical yield)\} ×100} \tn 
% Row Count 2 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH7: CHEM. BONDING \& MOLECULAR GEO.}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{formal charge = (\# valence shell electrons (free atom)) − (\# lone pair electrons −(1/2) \# bonding electrons)} \tn 
% Row Count 3 (+ 3)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Bond energy,diatomic molecule: XY(g)⟶ X(g) + Y(g)   D\textasciicircum{}X–Y\textasciicircum{}=ΔH°} \tn 
% Row Count 5 (+ 2)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Enthalpy change: ΔH = ƩD\textasciicircum{}bonds broken\textasciicircum{} – ƩD\textasciicircum{}bonds formed\textasciicircum{}} \tn 
% Row Count 7 (+ 2)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Lattice energy, solid MX: MX(s)⟶ M\textasciicircum{}n+\textasciicircum{}(g) +X\textasciicircum{}n−\textasciicircum{}(g)     ΔH\textasciicircum{}lattice} \tn 
% Row Count 9 (+ 2)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Lattice energy, ionic crystal: ΔH\textasciicircum{}lattice\textasciicircum{} = (C(Z\textasciicircum{}+\textasciicircum{})(Z\textasciicircum{}−\textasciicircum{})) / Ro} \tn 
% Row Count 11 (+ 2)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 13: FUNDAMENTAL EQUILIBRIUM CONCEPTS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Qc={[}C{]}\textasciicircum{}c\textasciicircum{}{[}D{]}\textasciicircum{}d\textasciicircum{} / {[}A{]}\textasciicircum{}a\textasciicircum{}{[}B{]}\textasciicircum{}b\textasciicircum{}} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Qp= {[}PC{]}\textasciicircum{}c\textasciicircum{}{[}PD{]}\textasciicircum{}d\textasciicircum{} / {[}PA{]}\textasciicircum{}a\textasciicircum{}{[}PB{]}\textasciicircum{}b\textasciicircum{}} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{P = MRT} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{Kc = Qc at equilibrium} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{Kp = Qp at equilibrium} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{KP = Kc (RT)\textasciicircum{}Δn\textasciicircum{}} \tn 
% Row Count 6 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}

\begin{tabularx}{5.377cm}{X}
\SetRowColor{DarkBackground}
\mymulticolumn{1}{x{5.377cm}}{\bf\textcolor{white}{CH 16: THERMODYNAMICS}}  \tn
% Row 0
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔS= qrev/T} \tn 
% Row Count 1 (+ 1)
% Row 1
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{S = k ln W} \tn 
% Row Count 2 (+ 1)
% Row 2
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔS=k ln(Wf/Wi)} \tn 
% Row Count 3 (+ 1)
% Row 3
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔS° = \seqsplit{∑νS°(products)−∑νS°(reactants)}} \tn 
% Row Count 4 (+ 1)
% Row 4
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{ΔS=qrev/T} \tn 
% Row Count 5 (+ 1)
% Row 5
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔSuniv = ΔSsys + ΔSsurr} \tn 
% Row Count 6 (+ 1)
% Row 6
\SetRowColor{LightBackground}
\mymulticolumn{1}{x{5.377cm}}{\seqsplit{ΔSuniv=ΔSsys+ΔSsurr=ΔSsys+} (qsurr/T)} \tn 
% Row Count 7 (+ 1)
% Row 7
\SetRowColor{white}
\mymulticolumn{1}{x{5.377cm}}{ΔG = ΔH − TΔS} \tn 
% Row Count 8 (+ 1)
\hhline{>{\arrayrulecolor{DarkBackground}}-}
\end{tabularx}
\par\addvspace{1.3em}


% That's all folks
\end{multicols*}

\end{document}