\documentclass[10pt,a4paper]{article} % Packages \usepackage{fancyhdr} % For header and footer \usepackage{multicol} % Allows multicols in tables \usepackage{tabularx} % Intelligent column widths \usepackage{tabulary} % Used in header and footer \usepackage{hhline} % Border under tables \usepackage{graphicx} % For images \usepackage{xcolor} % For hex colours %\usepackage[utf8x]{inputenc} % For unicode character support \usepackage[T1]{fontenc} % Without this we get weird character replacements \usepackage{colortbl} % For coloured tables \usepackage{setspace} % For line height \usepackage{lastpage} % Needed for total page number \usepackage{seqsplit} % Splits long words. %\usepackage{opensans} % Can't make this work so far. Shame. Would be lovely. \usepackage[normalem]{ulem} % For underlining links % Most of the following are not required for the majority % of cheat sheets but are needed for some symbol support. \usepackage{amsmath} % Symbols \usepackage{MnSymbol} % Symbols \usepackage{wasysym} % Symbols %\usepackage[english,german,french,spanish,italian]{babel} % Languages % Document Info \author{Alexcharaon} \pdfinfo{ /Title (physik-q1.pdf) /Creator (Cheatography) /Author (Alexcharaon) /Subject (Physik Q1 Cheat Sheet) } % Lengths and widths \addtolength{\textwidth}{6cm} \addtolength{\textheight}{-1cm} \addtolength{\hoffset}{-3cm} \addtolength{\voffset}{-2cm} \setlength{\tabcolsep}{0.2cm} % Space between columns \setlength{\headsep}{-12pt} % Reduce space between header and content \setlength{\headheight}{85pt} % If less, LaTeX automatically increases it \renewcommand{\footrulewidth}{0pt} % Remove footer line \renewcommand{\headrulewidth}{0pt} % Remove header line \renewcommand{\seqinsert}{\ifmmode\allowbreak\else\-\fi} % Hyphens in seqsplit % This two commands together give roughly % the right line height in the tables \renewcommand{\arraystretch}{1.3} \onehalfspacing % Commands \newcommand{\SetRowColor}[1]{\noalign{\gdef\RowColorName{#1}}\rowcolor{\RowColorName}} % Shortcut for row colour \newcommand{\mymulticolumn}[3]{\multicolumn{#1}{>{\columncolor{\RowColorName}}#2}{#3}} % For coloured multi-cols \newcolumntype{x}[1]{>{\raggedright}p{#1}} % New column types for ragged-right paragraph columns \newcommand{\tn}{\tabularnewline} % Required as custom column type in use % Font and Colours \definecolor{HeadBackground}{HTML}{333333} \definecolor{FootBackground}{HTML}{666666} \definecolor{TextColor}{HTML}{333333} \definecolor{DarkBackground}{HTML}{4A4A4A} \definecolor{LightBackground}{HTML}{F3F3F3} \renewcommand{\familydefault}{\sfdefault} \color{TextColor} % Header and Footer \pagestyle{fancy} \fancyhead{} % Set header to blank \fancyfoot{} % Set footer to blank \fancyhead[L]{ \noindent \begin{multicols}{3} \begin{tabulary}{5.8cm}{C} \SetRowColor{DarkBackground} \vspace{-7pt} {\parbox{\dimexpr\textwidth-2\fboxsep\relax}{\noindent \hspace*{-6pt}\includegraphics[width=5.8cm]{/web/www.cheatography.com/public/images/cheatography_logo.pdf}} } \end{tabulary} \columnbreak \begin{tabulary}{11cm}{L} \vspace{-2pt}\large{\bf{\textcolor{DarkBackground}{\textrm{Physik Q1 Cheat Sheet}}}} \\ \normalsize{by \textcolor{DarkBackground}{Alexcharaon} via \textcolor{DarkBackground}{\uline{cheatography.com/219101/cs/48477/}}} \end{tabulary} \end{multicols}} \fancyfoot[L]{ \footnotesize \noindent \begin{multicols}{3} \begin{tabulary}{5.8cm}{LL} \SetRowColor{FootBackground} \mymulticolumn{2}{p{5.377cm}}{\bf\textcolor{white}{Cheatographer}} \\ \vspace{-2pt}Alexcharaon \\ \uline{cheatography.com/alexcharaon} \\ \end{tabulary} \vfill \columnbreak \begin{tabulary}{5.8cm}{L} \SetRowColor{FootBackground} \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Cheat Sheet}} \\ \vspace{-2pt}Published 1st October, 2026.\\ Updated 1st October, 2026.\\ Page {\thepage} of \pageref{LastPage}. \end{tabulary} \vfill \columnbreak \begin{tabulary}{5.8cm}{L} \SetRowColor{FootBackground} \mymulticolumn{1}{p{5.377cm}}{\bf\textcolor{white}{Sponsor}} \\ \SetRowColor{white} \vspace{-5pt} %\includegraphics[width=48px,height=48px]{dave.jpeg} Measure your website readability!\\ www.readability-score.com \end{tabulary} \end{multicols}} \begin{document} \raggedright \raggedcolumns % Set font size to small. Switch to any value % from this page to resize cheat sheet text: % www.emerson.emory.edu/services/latex/latex_169.html \footnotesize % Small font. \begin{tabularx}{17.67cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{17.67cm}}{\bf\textcolor{white}{Physik Q1}} \tn % Row 0 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{Ladungstr{\"a}ger in elektrischen und magnetischen Feldern}}} \tn % Row Count 2 (+ 2) % Row 1 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- gleiche Ladungen sto{\ss}en sich ab, unterschiedliche Ladungen ziehen sich an} \tn % Row Count 4 (+ 2) % Row 2 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- "+" -{}-\textgreater{} "-"} \tn % Row Count 5 (+ 1) % Row 3 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 5 (+ 0) % Row 4 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{Elektrische Ladung "Q" ("q")}}} \tn % Row Count 6 (+ 1) % Row 5 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- entweder positiv "+" oder negativ "-"} \tn % Row Count 7 (+ 1) % Row 6 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- ein neutraler K{\"o}rper besitzt gleich viele {\emph{positive}} wie {\emph{negative Ladungstr{\"a}ger}}} \tn % Row Count 9 (+ 2) % Row 7 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- negative Ladung (Q\textless{}0) ≙ Elektronenüberschuss} \tn % Row Count 10 (+ 1) % Row 8 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- positive Ladung (Q\textgreater{}0) ≙ Elektronenmangel} \tn % Row Count 11 (+ 1) % Row 9 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- bei {\emph{elektrischen Ladungen}} wirkt eine {\emph{elektrische Kraft}}} \tn % Row Count 13 (+ 2) % Row 10 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- gleichnamige Ladungen sto{\ss}en sich ab \{\{nl\}\} - ungleichnamige Ladungen ziehen sich an} \tn % Row Count 15 (+ 2) % Row 11 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Einheit der elektrischen Ladung:} \tn % Row Count 16 (+ 1) % Row 12 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Flie{\ss}t ein Strom I der St{\"a}rke 1 A (Ampère) für 1 Sekunde, so wird eine Ladungsmenge Q von 1 C (Coulomb) übertragen:} \tn % Row Count 19 (+ 3) % Row 13 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{-\textgreater{} 1 C = 1 A * 1 s \{\{nl\}\} bzw. \{\{nl\}\} Ladung = Stromst{\"a}rke * Zeit} \tn % Row Count 21 (+ 2) % Row 14 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{1 {[}Q{]} = 1 C (Coulomb)} \tn % Row Count 22 (+ 1) % Row 15 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 22 (+ 0) % Row 16 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{Influenz}}} \tn % Row Count 23 (+ 1) % Row 17 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- Umverteilung der elektrischen Ladung eines Objekts durch ein elektrisches Feld} \tn % Row Count 25 (+ 2) % Row 18 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- durch das elektrische Feld wird die Bewegung von Ladungstr{\"a}gern initiiert} \tn % Row Count 27 (+ 2) % Row 19 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Bei einem Elektroskop: \{\{nl\}\} - "geringe Ladung" führt zu geringem Ausschlag \{\{nl\}\} - "gro{\ss}e Ladung" führt zu starkem Ausschlag} \tn % Row Count 30 (+ 3) \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{17.67cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{17.67cm}}{\bf\textcolor{white}{Physik Q1 (cont)}} \tn % Row 20 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{-\textgreater{} die 'Kraft' des elektrischen Feldes geht mit der St{\"a}rke der Ladung einher} \tn % Row Count 2 (+ 2) % Row 21 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 2 (+ 0) % Row 22 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{Die elektrische Feldst{\"a}rke E\textasciicircum{}-\textgreater{}\textasciicircum{}}}} \tn % Row Count 3 (+ 1) % Row 23 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- E\textasciicircum{}-\textgreater{}\textasciicircum{} = F\textasciicircum{}-\textgreater{}\textasciicircum{}/Q} \tn % Row Count 4 (+ 1) % Row 24 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- die elektrische Feldst{\"a}rke E ist der Quotient (und somit die Proportionalit{\"a}tskonstante) aus der elektrischen Kraft F, die auf eine Ladung Q wirkt} \tn % Row Count 7 (+ 3) % Row 25 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{{[}E\textasciicircum{}-\textgreater{}\textasciicircum{}{]} = N/C (Newton / Coulomb)} \tn % Row Count 8 (+ 1) % Row 26 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 8 (+ 0) % Row 27 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 8 (+ 0) % Row 28 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{Die wirkweise eines elektrischen Feldes}}} \tn % Row Count 9 (+ 1) % Row 29 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- Die Feldst{\"a}rke nimmt nach au{\ss}en hin ab} \tn % Row Count 10 (+ 1) % Row 30 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- "homogenes elektrisches Feld" \{\{nl\}\} -\textgreater{} die Feldst{\"a}rke ist im inneren Bereich überall gleich gro{\ss} (-\textgreater{} homogen)} \tn % Row Count 13 (+ 3) % Row 31 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{\{\{popup="https://www.lernhelfer.de/sites/default/files/styles/lightbox/public/lexicon/image/BWS-PHY-0104-09.gif?itok=c5vYZzhf"\}\}Beispielfoto\{\{/link\}\} \{\{nl\}\} -\textgreater{} durch beide Ladungen wird jeweils eine Kraft F\textasciicircum{}-\textgreater{}\textasciicircum{}\textasciitilde{}1\textasciitilde{} und F\textasciicircum{}-\textgreater{}\textasciicircum{}\textasciitilde{}2\textasciitilde{} auf die positive Probeladung ausgeübt. Mit einem Kr{\"a}fteparallelogramm l{\"a}sst sich die resultierende Kraft F\textasciicircum{}-\textgreater{}\textasciicircum{}\textasciitilde{}res\textasciitilde{} ermitteln. Die Feldlinien geben also immer die Kraft auf eine positive Probeladung an.} \tn % Row Count 22 (+ 9) % Row 32 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{\{\{link="https://media.springernature.com/lw685/springer-static/image/chp\%3A10.1007\%2F978-3-662-67936-4\_18/MediaObjects/155876\_9\_De\_18\_Fig22\_HTML.png"\}\}Elektrisches Feld mit zwei positiven Punktladungen} \tn % Row Count 27 (+ 5) % Row 33 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Regeln für das Zeichnen von Punktladungen:} \tn % Row Count 28 (+ 1) % Row 34 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Feldlinien verlaufen von "+" zu "-"} \tn % Row Count 29 (+ 1) % Row 35 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- Feldlinien stehen {\bf{immer}} senkrecht zur Leiteroberfl{\"a}che} \tn % Row Count 31 (+ 2) \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{17.67cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{17.67cm}}{\bf\textcolor{white}{Physik Q1 (cont)}} \tn % Row 36 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Feldlinien schneiden sich {\bf{nie}}} \tn % Row Count 1 (+ 1) % Row 37 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- Feldlinien sind nur ein {\bf{Hilfsmittel}} zum {\bf{Visualisieren}} und {\bf{nicht real}}} \tn % Row Count 3 (+ 2) % Row 38 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- die Dichte der Feldlinien ist proportional zur elektrischen Feldst{\"a}rke E} \tn % Row Count 5 (+ 2) % Row 39 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Wovon h{\"a}ngt das elektrische Feld ab:} \tn % Row Count 6 (+ 1) % Row 40 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Distanz der Ladungstr{\"a}ger} \tn % Row Count 7 (+ 1) % Row 41 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- St{\"a}rke der Ladungen} \tn % Row Count 8 (+ 1) % Row 42 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Medium, in dem sich die Ladungen befinden} \tn % Row Count 9 (+ 1) % Row 43 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 9 (+ 0) % Row 44 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{{\bf{das Gesetz von Coulomb}}} \tn % Row Count 10 (+ 1) % Row 45 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{- F \textbackslash{}\textasciitilde{} q} \tn % Row Count 11 (+ 1) % Row 46 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- F \textbackslash{}\textasciitilde{} r\textasciicircum{}-2\textasciicircum{} bzw. F \textbackslash{}\textasciitilde{} 1/r\textasciicircum{}2\textasciicircum{}} \tn % Row Count 12 (+ 1) % Row 47 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{-\textgreater{} F\textbackslash{}\textasciitilde{} k * ((q\textasciitilde{}1\textasciitilde{} * q\textasciitilde{}2\textasciitilde{}) / r\textasciicircum{}2\textasciicircum{}) \{\{nl\}\} (k = Proportionalit{\"a}tskonstante)} \tn % Row Count 14 (+ 2) % Row 48 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{=\textgreater{} F\textasciitilde{}er\textasciitilde{} = k * ((q\textasciitilde{}1\textasciitilde{} * q\textasciitilde{}2\textasciitilde{}) / r\textasciicircum{}2\textasciicircum{}) \{\{nl\}\} \textless{}=\textgreater{} F\textasciitilde{}er\textasciitilde{}*r\textasciicircum{}2\textasciicircum{} = k * q\textasciitilde{}1\textasciitilde{} * q\textasciitilde{}2\textasciitilde{} \{\{nl\}\} \textless{}=\textgreater{} k = (F\textasciitilde{}er\textasciitilde{}*r\textasciicircum{}2\textasciicircum{}) / (q\textasciitilde{}1\textasciitilde{}*q\textasciitilde{}2\textasciitilde{})} \tn % Row Count 17 (+ 3) % Row 49 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{(Kursergebnis \{\{nl\}\}F\textasciitilde{}er\textasciitilde{} = 280,861 N \{\{nl\}\} q\textasciitilde{}1\textasciitilde{} = 10\textasciicircum{}-5\textasciicircum{} C \{\{nl\}\} q\textasciitilde{}2\textasciitilde{} = 5*10\textasciicircum{}-6\textasciicircum{} C \{\{nl\}\} r = 0,04 m \{\{nl\}\} \{\{nl\}\} =\textgreater{} 280,861 = k * ((10\textasciicircum{}-5\textasciicircum{} * 5*10\textasciicircum{}-6\textasciicircum{})/0,04\textasciicircum{}2\textasciicircum{}) \{\{nl\}\} \textless{}=\textgreater{} k = ((280,861 * 0,04\textasciicircum{}2\textasciicircum{})/(10\textasciicircum{}-5\textasciicircum{} * 5*10\textasciicircum{}-6\textasciicircum{})) \{\{nl\}\} =\textgreater{} k = 8,9876 * 10\textasciicircum{}9\textasciicircum{} (N * m\textasciicircum{}2\textasciicircum{}) / C\textasciicircum{}2\textasciicircum{} \{\{nl\}\})} \tn % Row Count 23 (+ 6) % Row 50 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{-\textgreater{} Die Kraft, die zwei kugelf{\"o}rmige bzw. punktf{\"o}rmige Ladungen q\textasciitilde{}1\textasciitilde{} \& q\textasciitilde{}2\textasciitilde{} aufeinander auswirken, ist definiert durch F = k*(q\textasciitilde{}1\textasciitilde{} * q\textasciitilde{}2\textasciitilde{})/r\textasciicircum{}2\textasciicircum{} \{\{nl\}\} k ist dabei die Coulomb-Konstante. Diese ist definiert durch "k = 1/(4π*ε\textasciitilde{}0\textasciitilde{}) ≈ 8,99*10\textasciicircum{}9\textasciicircum{} (N * m\textasciicircum{}2\textasciicircum{}) / C\textasciicircum{}2\textasciicircum{} \{\{nl\}\} ε\textasciitilde{}0\textasciitilde{} = elektrische Feldkonstante} \tn % Row Count 30 (+ 7) \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{17.67cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{17.67cm}}{\bf\textcolor{white}{Physik Q1 (cont)}} \tn % Row 51 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 0 (+ 0) % Row 52 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Elektrische Feldkonstante:} \tn % Row Count 1 (+ 1) % Row 53 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{ε\textasciitilde{}0\textasciitilde{}*r\textasciicircum{}2\textasciicircum{} = (q\textasciitilde{}1\textasciitilde{}*q\textasciitilde{}2\textasciitilde{})/(4π*F)} \tn % Row Count 2 (+ 1) % Row 54 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{ε\textasciitilde{}0 Lit\textasciitilde{} ≈ 8,854*10\textasciicircum{}-12\textasciicircum{} C\textasciicircum{}2\textasciicircum{}/(N*m\textasciicircum{}2\textasciicircum{})} \tn % Row Count 3 (+ 1) % Row 55 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 3 (+ 0) % Row 56 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{{\bf{elektrische Feldst{\"a}rke in einem homogenen elektrischen Feld}}} \tn % Row Count 5 (+ 2) % Row 57 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{I \textbackslash{}\textasciitilde{} U \{\{nl\}\} \& \{\{nl\}\} E \textbackslash{}\textasciitilde{} I \{\{nl\}\} =\textgreater{} E \textbackslash{}\textasciitilde{} U} \tn % Row Count 6 (+ 1) % Row 58 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{die elektrische Feldst{\"a}rke E eines homogenen elektrischen Feldes ist proportional zur Spannung der beiden Ladungstr{\"a}gern U und dem Kehrwert des Abstandes zwischen den Ladungstr{\"a}gern d (1/d)} \tn % Row Count 10 (+ 4) % Row 59 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{im homogenen Feld gilt also: \{\{nl\}\} E = U/d} \tn % Row Count 11 (+ 1) % Row 60 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{das hei{\ss}t: \{\{nl\}\} F\textasciitilde{}el\textasciitilde{} = q * E, da E = F\textasciitilde{}el\textasciitilde{}/q \{\{nl\}\} =\textgreater{} F\textasciitilde{}el\textasciitilde{} = q * (U/d) \{\{nl\}\} \{\{nl\}\} U:anliegende Spannung {[}V{]} \{\{nl\}\} d: abstand der Ladungstr{\"a}ger {[}m{]} \{\{nl\}\} q: elektrische Ladung {[}C{]}} \tn % Row Count 15 (+ 4) % Row 61 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 15 (+ 0) % Row 62 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{{\bf{Millikan Versuch}}} \tn % Row Count 16 (+ 1) % Row 63 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{Ziel: "Gibt es eine kleinste Ladung?"} \tn % Row Count 17 (+ 1) % Row 64 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{"Schwebemetode":} \tn % Row Count 18 (+ 1) % Row 65 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{- Plattenkondensator \{\{nl\}\} - Öltr{\"o}pfchen (Annahme: kugelf{\"o}rmig)} \tn % Row Count 20 (+ 2) % Row 66 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{F\textasciitilde{}el\textasciitilde{} = q * U/d \{\{nl\}\} F\textasciitilde{}G\textasciitilde{} = m * g \{\{nl\}\} =\textgreater{} F\textasciitilde{}G\textasciitilde{} = V * ρ * g \{\{nl\}\} =\textgreater{} F\textasciitilde{}G\textasciitilde{} = 4/3π * r\textasciicircum{}3\textasciicircum{} * ρ * g \{\{nl\}\}} \tn % Row Count 23 (+ 3) % Row 67 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{Auftriebskraft: \{\{nl\}\}F\textasciitilde{}A\textasciitilde{} (zeigt nach oben) \{\{nl\}\} F\textasciitilde{}A\textasciitilde{} = 4/3πr\textasciicircum{}3\textasciicircum{} * ρ\textasciitilde{}Luft\textasciitilde{} * g \{\{nl\}\} Luft zwischen Platten -\textgreater{} Auftrieb in Luft} \tn % Row Count 26 (+ 3) % Row 68 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{-\textgreater{} F\textasciitilde{}G\textasciitilde{} - F\textasciitilde{}A\textasciitilde{} = F\textasciitilde{}G'\textasciitilde{} \{\{nl\}\}F\textasciitilde{}G'\textasciitilde{} = 4/3πr\textasciicircum{}3\textasciicircum{} * g (ρ\textasciitilde{}Öl\textasciitilde{} - ρ\textasciitilde{}Luft\textasciitilde{}) \{\{nl\}\} =\textgreater{} F\textasciitilde{}G'\textasciitilde{} = 4/3πr\textasciicircum{}3\textasciicircum{} * g * ρ' \{\{nl\}\} \{\{nl\}\} Es gilt F\textasciitilde{}G\textasciitilde{} = F\textasciitilde{}el\textasciitilde{} \{\{nl\}\} =\textgreater{} 4/3πr\textasciicircum{}3\textasciicircum{} * ρ' * g = q * U/d \{\{nl\}\} =\textgreater{} q = (4/3πr\textasciicircum{}3\textasciicircum{} * ρ' * g * d) / U} \tn % Row Count 31 (+ 5) \end{tabularx} \par\addvspace{1.3em} \begin{tabularx}{17.67cm}{X} \SetRowColor{DarkBackground} \mymulticolumn{1}{x{17.67cm}}{\bf\textcolor{white}{Physik Q1 (cont)}} \tn % Row 69 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{Radius bestimmen: \{\{nl\}\} F\textasciitilde{}g\textasciitilde{} = F\textasciitilde{}A\textasciitilde{} * F\textasciitilde{}R\textasciitilde{} |-F\textasciitilde{}A\textasciitilde{} \{\{nl\}\} F\textasciitilde{}G\textasciitilde{} - F\textasciitilde{}A\textasciitilde{} = F\textasciitilde{}R\textasciitilde{} \{\{nl\}\} 4/3πr\textasciicircum{}3\textasciicircum{} * g (ρ\textasciitilde{}Öl\textasciitilde{} - ρ\textasciitilde{}Luft\textasciitilde{}) = 6 πr * η * v |r, π kürzen \{\{nl\}\} 4/3r\textasciicircum{}2\textasciicircum{} * g * ρ' = 6 * η * v | * (3/4*g*ρ') \{\{nl\}\} r\textasciicircum{}2\textasciicircum{} = (9 * η * v) / (2 * ρ' * g) | Quadratwurzel \{\{nl\}\} r = Quadratwurzel( (9 * η * v) / (2 * ρ' * g) )} \tn % Row Count 7 (+ 7) % Row 70 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Herr Millikan hat mit diesem Versuch nachgewiesen, dass es diskrete Ladungen gibt, die vielfache von einer {\emph{kleinsten Ladung}} sind. Diese kleinste Ladungen nennen wir {\bf{Elementarladung e}} \{\{nl\}\} e = 1,602176634 * 10 \textasciicircum{}-19\textasciicircum{} \{\{nl\}\} ein Elektron hat genau diese Elementarladung als Ladung} \tn % Row Count 13 (+ 6) % Row 71 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{} \tn % Row Count 13 (+ 0) % Row 72 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{{\bf{Potential und Spannung im homogenen elektrischen Feld (z.B. Plattenkondensator)}}} \tn % Row Count 15 (+ 2) % Row 73 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{s = Strecke zwischen pos. Ladungstr{\"a}ger und pos. Platte} \tn % Row Count 17 (+ 2) % Row 74 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{wir betrachten die Bewegung des pos. Ladungstr{\"a}gers} \tn % Row Count 19 (+ 2) % Row 75 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{W = F * s (Arbeit = Work = W)} \tn % Row Count 20 (+ 1) % Row 76 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{Wir wissen: F = q * E \{\{nl\}\} =\textgreater{}W = q * E * s \{\{nl\}\} W/q = φ} \tn % Row Count 22 (+ 2) % Row 77 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{s\textasciitilde{}1\textasciitilde{} = Abstand zur neuen Position \{\{nl\}\} s\textasciitilde{}2\textasciitilde{} = Abstand zwischen neuer Position und pos. Platte} \tn % Row Count 24 (+ 2) % Row 78 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{W(1 -\textgreater{} 2) = q* E * (s\textasciitilde{}1\textasciitilde{} - s\textasciitilde{}2\textasciitilde{}) \{\{nl\}\} = q * (Es\textasciitilde{}1\textasciitilde{} - Es\textasciitilde{}2\textasciitilde{}) \{\{nl\}\} = q * (φ\textasciitilde{}1\textasciitilde{} - φ\textasciitilde{}2\textasciitilde{}) \{\{nl\}\} = q * Δφ} \tn % Row Count 27 (+ 3) % Row 79 \SetRowColor{LightBackground} \mymulticolumn{1}{x{17.67cm}}{die {\bf{Potentialdifferenz Δφ}} hei{\ss}t {\bf{elektrische Spannung U}}} \tn % Row Count 29 (+ 2) % Row 80 \SetRowColor{white} \mymulticolumn{1}{x{17.67cm}}{U = W/q \{\{nl\}\} \textless{}=\textgreater{} W= q*U \{\{nl\}\} {[}U{]} = {[}W{]}/{[}q{]} = J/As = V (1 V*As = 1 J)} \tn % Row Count 31 (+ 2) \hhline{>{\arrayrulecolor{DarkBackground}}-} \end{tabularx} \par\addvspace{1.3em} \end{document}